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Maurinko [17]
3 years ago
13

Find the 1st and 3rd quartile: 1,0,2,0,63,34,27,13

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

The 1st quartile equals: 0.5

the 3rd quartile equals: 30.5

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If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.
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Answer:

100

Step-by-step explanation:

We have the sum of first n terms of an AP,

Sn = n/2 [2a+(n−1)d]

Given,

36= 6/2 [2a+(6−1)d]

12=2a+5d ---------(1)

256= 16/2 [2a+(16−1)d]

32=2a+15d ---------(2)

Subtracting, (1) from (2)

32−12=2a+15d−(2a+5d)

20=10d ⟹d=2

Substituting for d in (1),

12=2a+5(2)=2(a+5)

6=a+5 ⟹a=1

∴ The sum of first 10 terms of an AP,

S10 = 10/2 [2(1)+(10−1)2]

S10 =5[2+18]

S10 =100

This is the sum of the first 10 terms.

Hope it will help.

4 0
3 years ago
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Step-by-step explanation:

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