Answer:
- The molar mass of the solute, in order to convert from moles of solute to grams of solute.
- The density of solution, to convert from volume of solution to mass of solution.
Explanation:
Hello,
In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:
- The molar mass of the solute, in order to convert from moles of solute to grams of solute.
- The density of solution, to convert from volume of solution to mass of solution.
For instance, if a 1-M solution of HCl has a density of 1.125 g/mL, we can compute the w/w% as follows:

Whereas the first factor corresponds to the molar mass of HCl, the second one the conversion from L to mL of solution and the third one the density to express in terms of grams of solution.
Regards.
Answer:
The answer is 1,185,000 cal or 1,185 kcal
Explanation:
We convert the weight of butane (C₄H₁₀, MW = 58) to mole
n = m/M = 100.0 / 58 = 1.724 mol
The heat of combustion of 100.0 g or 1.724 mol of butane is
H(kJ) = 1.724 mol x 2,877.5 kJ/mol = 4,960.8 kJ
Then we convert the unit to calories
H(cal) = 4,960.8 kJ / 4.184 kJ/kcal = 1,185 kcal = 1,185,000 cal
Answer:
Oh it is convention
Explanation:
because the heat transfer is through fluids
Answer:
C
Explanation:
cause it looks right and I also studied but wait til someone gives another answer