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marshall27 [118]
3 years ago
12

13.Which shows the order of increasing ionization energy?

Chemistry
1 answer:
Mademuasel [1]3 years ago
5 0
I think it is b. Ga, Ge, As, Se
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COMPARE: Identify three ways that a biologist’s research is similar to an astronomer’s.
dalvyx [7]
  1. Biologist and astronomer both use tools that magnify  so they are able to view minute objects. Astronomers use telescopes while biologists use microscopes.
  2. They both require data science due to the enormous data they are collecting that needs to be analyzed. Astronomers are collecting data on millions of stars and galaxies. Biologists require data science to analyze the enormous genomic data from populations.
  3. Both fields involve making new  discoveries due to the enormity of the scale in their scopes. Biologists and astronomy attempt to find new planets and those that could harbor extra-terrestrial life while biology attempts to find new undiscovered species of organisms on earth.

8 0
3 years ago
For each reaction, find the value of ΔSo. Report the value with the appropriate sign. (a) 3 NO2(g) + H2O(l) → 2 HNO3(l) + NO(g)
aev [14]

Answer:

ΔS° = -268.13 J/K

Explanation:

Let's consider the following balanced equation.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:

ΔS° = ∑np.Sp° - ∑nr.Sr°

where,

ni are the moles of reactants and products

Si are the standard molar entropies of reactants and products

ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]

ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]

ΔS° = -268.13 J/K

7 0
3 years ago
During a reaction, the enthalpy of formation of an intermediate is -286
Darina [25.2K]

Answer:

O A. -572 kJ

Explanation:

3 0
2 years ago
Ten pints of 15 % salt solution are mixed with 15 pints of 10 % salt solution. What is the
sergij07 [2.7K]
Concentration\ rate=\frac{mass\ of\ product}{mass\ of\ substance}*100\%\\\\
15\%=\frac{m_1}{ms_1}*100\%\\ms_1=10pints\\
15\%=\frac{m_1}{10}*100\%\\
\frac{15}{100}=\frac{m_1}{10}\ \ |*10\\
m_1=\frac{150}{100}=1,5pints\\\\
10\%=\frac{m_2}{15}*100\%\\
0,1=\frac{m_2}{15}\ \ |*15\\
1,5=m_2\\
Resulting\ solution:\\
ms=ms_1+ms_2=15+10=25pints\\m=m_1+m_2=1,5+1,5=3pints
\\\frac{m}{ms}*100\%=\frac{3}{25}*100\%=12\%
7 0
3 years ago
4. Which class of matter is the least evenly
lys-0071 [83]

Answer:

Pure iron sulfide is homogeneous (uniform in appearance and properties), shows constant composition (a consistent ratio of iron to sulfur throughout any sample of it, large or small), consists of molecules all of one type, is no longer separable into two separate substances without another chemical reaction, and is .

Explanation:

Mixtures in two or more phases are heterogeneous mixtures. ... The exception would be solutions that contain another phase of matter. For example, you can make a homogeneous solution of sugar and water, but if there are crystals in the solution, it becomes a heterogeneous mixture.

8 0
3 years ago
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