Take x-2 and insert it into 2x^2 + 3x-2 where the x is located
2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2
Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2 = x^2 -4x + 4
2(x-2)^2 = 2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8
Now that 2(x-2)^2 is done lets move on to 3(x-2).
Use the distributive property and distribute the 3
3(x-2) = 3x - 6
All that is left is the -2
Now lets put it all together
2(x-2)^2 + 3(x-2)-2
2x^2 - 8x + 8 + 3x - 6 - 2
Now combine all our like terms
2x^2 - 8x + 8 + 3x - 6 - 2
Combine: 2x^2 = 2x^2
Combine: -8x + 3x = -5x
Combine: 8 - 6 - 2 = 0
So all we have left is
2x^2 - 5x
Answer:
B. ( –3, –4)
C. ( 4, 17 )
Step-by-step explanation:
Function: y = 3x + 5
Using method of elimination
A. (2, –1)
x = 2, y = -1
-1 = 3 (2) + 5
-1 ≠ 11
This option is incorrect!
B. ( –3, –4)
x = -3, y = -4
-4 = 3 (-3) + 5
-4 = - 9 + 5
-4 = -4
This option is correct!
C. ( 4, 17 )
x = 4, y = 17
17 = 3 (4) + 5
17 = 12 + 5
17 = 17
This option is correct!
D. ( 3, 8 )
x = 3, y = 8
8 = 3 (3) + 5
8 = 9 + 5
8 = 14
This option is incorrect!
Rounding 2 SF would give you 19
The answer is zero point four three
You could also write this answer as 0.43
