If the perimeter of the regular hexagon shown above is 78 centimeters, what is the length of each side?

What value should go in the empty box to complete the calculation for finding the product of 73.458 × 0.39? the empty box in the

leonid [27]

The correct answer is 30.59

7 0

2 years ago

PLEASE HELP ME ILL MAKE BRAINLIEST!!!!! <br> I need the correct answer

guajiro [1.7K]

Answer:

56.7

Step-by-step explanation:

Hello There!

<u>Trigonometric Ratios</u>

sin = opposite divided by hypotenuse

cos = adjacent divided by hypotenuse

tan = opposite divided by adjacent

we need to find x and we are given its opposite side length and the hypotenuse

so the trigonometric ratio we need to use is sin

knowing that sin = opposite side divided by hypotenuse we create an equation

$sin(x)=\frac{51}{61}\\\frac{51}{61} = .8360655738\\arcsin(sinX)=x\\arcsin(.8360655738)=56.72695659$

our final step is to round to the nearest tenth of a degree

so we can conclude that the measure of angle A is 56.7

note: arcsin = inverse of sin

8 0

2 years ago

Read 2 more answers

Ms. Placencio weighed 153 pounds in 2018. She now weighs 132 pounds. What is the percent change round to the nearest tenths plac

Lera25 [3.4K]

Answer:17.7%

Step-by-step explanation:

132 x

____=_____

153 100

132(100)=153(x)

13200=153x

__________

153 153

x=82.3

100-82.3=17.7

4 0

2 years ago

Find the area of the figure. round your answer to the nearest hundredth

liraira [26]

Answer: 84.14

Step-by-step explanation:

Area of the rectangle is L*W=B*H

14*5=70

To find the area of the half circle we must use the formula pi r^2/2

r=radius

and the radius is 6 because we add 4 and 4 and need to get to 14

because the line below it is 14 and it is a rectangle so the lengths are the same.

Diameter=6

So radius =3

pi (3)^2/2=

9/2 pi + 70=

84.14

6 0

3 years ago

Read 2 more answers

Find dy/dx by implicit differentiation for ysin(y) = xcos(x)

tatyana61 [14]

Answer:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

Step-by-step explanation:

So we have:

$y\sin(y)=x\cos(x)$

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

$\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]$

Let's do each side individually.

Left Side:

We have:

$\frac{d}{dx}[y\sin(y)]$

We can use the product rule:

$(uv)'=u'v+uv'$

So, our derivative is:

$=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]$

We must implicitly differentiate for y. This gives us:

$=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]$

For the sin(y), we need to use the chain rule:

$u(v(x))'=u'(v(x))\cdot v'(x)$

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

$=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})$

Simplify:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}$

And we are done for the right.

Right Side:

We have:

$\frac{d}{dx}[x\cos(x)]$

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

$=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]$

Differentiate:

$=\cos(x)-x\sin(x)$

So, our entire equation is:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)$

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

$\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)$

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

And we're done!

5 0

2 years ago