A plane flies 1400 kilometres in 2 hours 30 minutes

Evaluate the expression when c=21 and d=4. c-5d

vekshin1

$\huge \boxed{\mathfrak{Question} \downarrow}$

Evaluate the expression when c = 21 and d = 4, c - 5d = ?

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

Given,

c = 21
d = 4
c - 5d = ?

Let's solve it now :-

$\sf \: c - 5d \\ \\ \sf \: Substitute \: the \: values \: of \: c \: and \: d \\ \\ \sf c - 5d \\ \rightarrow \sf(21) - 5(4) \\ \sf \rightarrow21 - 20 \\ = \boxed{\boxed{\bf \: 1}}$

The value of the expression is 1.

6 0

2 years ago

Find the sum of the arithmetic series: 10 + 4 + (-2) + ... + (-50)

Nastasia [14]

Answer is -220

if you have any doubts see the image 

6 0

2 years ago

An open box is made from an 8 by ten-inch rectangular piece of cardboard by cutting squares from each corner and folding up the

natka813 [3]

Please find the attachment.

Let x represent the side length of the squares.

We have been given that an open box is made from an 8 by ten-inch rectangular piece of cardboard by cutting squares from each corner and folding up the sides. We are asked to find the volume of the box.

The side of box will be $8-x-x=8-2x$ and $10-x-x=10-2x$ .

The height of the box will be $x$ .

The volume of box will be area of base times height.

$\text{Volume of box}=(8-2x)(10-2x)\cdot x$

Now we will use FOIL to simplify our expression.

$\text{Volume of box}=(80-16x-20x+4x^2)\cdot x$

$\text{Volume of box}=(80-36x+4x^2)\cdot x$

Now we will distribute x.

$\text{Volume of box}=80x-36x^2+4x^3$

$V(x)=80x-36x^2+4x^3$

Therefore, the volume of the box would be $V(x)=80x-36x^2+4x^3$ .

6 0

2 years ago

What is the mathematical relationship between the atomic radius (r) and the lattice parameter (a0) in the BCC structure? a. b. c

ryzh [129]

Answer: Lattice parameter, a = (4R)/(√3)

Step-by-step explanation:

The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.

The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.

If the diagonal of the base of the unit cell = x

(a^2) + (a^2) = (x^2)

x = a(√2)

Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.

Let the diagonal across the cube be y

Pythagoras theorem,

(a^2) + ((a(√2))^2) = (y^2)

(a^2) + 2(a^2) = (y^2) = 3(a^2)

y = a√3

But the diagonal through the cube = 4R (evident from the image in the first attachment)

y = 4R = a√3

a = (4R)/(√3)

QED!!!

8 0

2 years ago

Read 2 more answers

Not sure how to do this...

kumpel [21]

Answer:

(4,5)

Step-by-step explanation:

count up to the opposite point by the x-axis and the y axis.

hope this helps ! </3 ~ Alyssa. xoxo

3 0

2 years ago

Read 2 more answers