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dangina [55]
4 years ago
7

Can someone help me out please

Mathematics
1 answer:
Reptile [31]4 years ago
6 0
(4,1) there's the answer for you
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Solve 2x2 + 12x − 14 = 0 by completing the square.
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2x^2+12x-14=0\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2+6x-7=0\\\\x^2+2x\cdot3=7\ \ \ \ |add\ 3^2\ to\ both\ sides\\\\x^2+2x\cdot3+3^2=7+3^2\\\\(x+3)^2=7+9\\\\(x+3)^2=16\iff x+3=-\sqrt{16}\ or\ x+3=\sqrt{16}\\\\x+3=-4\ or\ x+3=4\\\\x=-4-3\ or\ x=4-3\\\\\boxed{x=-7\ or\ x=1}

3 0
3 years ago
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The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in gr
raketka [301]

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass <em>M</em>₀, the mass after 12 hours is half that:

1/2 <em>M</em>₀ = <em>M</em>₀ exp(12<em>k</em>)

for some decay constant <em>k</em>. Solve for this <em>k</em> :

1/2 = exp(12<em>k</em>)

ln(1/2) = 12<em>k</em>

<em>k</em> = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass <em>M</em>₀, the mass <em>M</em> remaining after time <em>t</em> is given by

<em>M</em> = <em>M</em>₀ exp(<em>kt </em>)

So if <em>M</em>₀ = 590 g and <em>t</em> = 36 h, plugging these into the equation with the previously determined value of <em>k</em> gives

<em>M</em> = 590 exp(36<em>k</em>) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

6 0
3 years ago
I need four lines that are parallel because I am doing a math project which is tainted glass
barxatty [35]

Answer:

Okay so what do we do

Step-by-step explanation:

6 0
3 years ago
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Can someone help me with this question please. I'll give the brainliest answer to whoever helps me.
Doss [256]

Answer: \sqrt[5]{y}

I realize its probably not the largest readable font. If you are having trouble reading it, it is the square root of y; however, there is a tiny little 5 in the upper left corner to indicate a fifth root. So you would read it out as "the fifth root of y"

The rule I'm using is

x^{1/n} = \sqrt[n]{x}

and the more general rule we could use is

x^{m/n} = \sqrt[n]{x^m}

where m = 1. This rule helps convert from rational exponent form (aka fractional exponents) to radical form.

5 0
4 years ago
Please answer both questions, I will report and delete unnecessary answers, or answer just trying to steal points.
Nostrana [21]

Answer:

1.  3x-2y=-6

2. 3x+2y=6

Step-by-step explanation:

7 0
3 years ago
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