Answer:
The solved problem is in the photo. Hope it helps.
When a man pushes a box across a floor, as he increases the force he applies horizontally to the box, then the kinetic friction remains the same.
To find the answer, we need to know about friction.
<h3>What is friction?</h3>
- Whenever a body moves, over the surface of another body, a force comes into play which acts parallel to the surface of contact and opposes the relative motion. This opposing force is called friction.
- There are two frictions acting on a surface.
- Static friction: It come into play between two bodies before when it starts moving. Self-adjusting force and the max value of it is called limiting static friction.
- Kinetic friction: It come into play between two bodies when it starts moving. It is not a self-adjusting force.
- As we increase applied force, kinetic friction will remain same.
Thus, we can conclude that, kinetic friction remains the same when we increase the applied force.
Learn more about the friction here:
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Answer:
The magnetic flux through the loop is 0.006284 m².T
Explanation:
Given;
radius of circular loop, r = 0.1 m
magnetic field strength, B = 0.2 T
Magnetic flux through the loop due to the external field is given as;
Φ = BAcosθ
where;
Φ is magnetic flux
B is the magnetic field strength
A is the area of the loop
θ is the angle of inclination of between the plane of the loop and external magnetic field
A = πr² = π(0.1)² = 0.03142 m²
θ = 0, since they are parallel
Φ = BAcosθ
Φ = 0.2 x 0.03142 x cos0
Φ = 0.006284 m².T
Answer:
r= 2.17 m
Explanation:
Conceptual Analysis:
The electric field at a distance r from a charge line of infinite length and constant charge per unit length is calculated as follows:
E= 2k*(λ/r) Formula (1)
Where:
E: electric field .( N/C)
k: Coulomb electric constant. (N*m²/C²)
λ: linear charge density. (C/m)
r : distance from the charge line to the surface where E calculates (m)
Known data
E= 2.9 N/C
λ = 3.5*10⁻¹⁰ C/m
k= 8.99 *10⁹ N*m²/C²
Problem development
We replace data in the formula (1):
E= 2*k*(λ/r)
2.9= 2*8.99 *10⁹*(3.5*10⁻¹⁰/r)
r =( 2*8.99 *10⁹*3.5*10⁻¹⁰) / (2.9)
r= 2.17 m
Answer:
1.05 J.
Explanation:
Kinetic Energy: This is the energy possessed by a body due to its motion. The S.I unit of kinetic energy is Joules (J). The formula of kinetic energy is given as
Ek = 1/2mv²................. Equation 1
Where Ek = kinetic energy, m = mass of the uniform rod, v = liner velocity of the rod.
But,
v = αr .......................... Equation 2
Where α = angular velocity of the rod, r = radius of the circle.
Given: α = 3.6 red/s, r = 120/2 = 60 cm = 0.6 m.
Substitute into equation 2
v = 3.6(0.6)
v = 2.16 m/s.
Also given: m = 450 g = 0.45 kg.
Substitute into equation 1
Ek = 1/2(0.45)(2.16²)
Ek = 1.05 J.
