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Dennis_Churaev [7]
3 years ago
12

What is supercooling? how can it be minimized?

Physics
1 answer:
8090 [49]3 years ago
3 0

<span>Supercooling is lowering the temperature of liquid below its freezing point. This is also known as the cooling of liquid. Supercooling can be minimized by cooling the liquid and steering the liquid fast while it is freezing. Freezers in the refrigerators shows the example activity of supercooling.</span>

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Sirius A has a luminosity of 26 LSun and a surface temperature of about 9400 K.What is its radius?
wlad13 [49]

Answer

Given,

Sirius A surface temperature,T = 9400 K

Sirius A luminosity,L = 26 L₀

L₀ is the luminosity of sun.

Radius of sun =  695700000 m

Temperature on sun surface = 5780 K

Luminous intensity is given by:-

L=4 \pi R^{2} \sigma T^{4}

Now

\frac{L}{L_{0}}=\frac{4 \pi R^{2} \sigma T^{4}}{4 \pi R_{0}^{2} \sigma T_{0}^{4}}=26

\Rightarrow \frac{R^{2} T^{4}}{R_{0}^{2} T_{0}^{4}}=26

\Rightarrow R^{2}=26 \times \frac{R^{2} T_{0}^{4}}{T^{4}}=26 \times \frac{695700000^{2} \times 5780^{4}}{9400^{4}}

R=1341246640\ m=1.34 \times 10^{9}

7 0
3 years ago
a pitcher throws a softball toward the home plate. when the ball hits the catchers mitt its horizontal velocity is 32 meters/sec
lora16 [44]

F = (mass)(acceleration) = ma

m = 0.2 kg

Vi = 32 m/s

t = 0.5 s

Vf = 0 m/s (since it was put to stop)

a=(Vf-Vi)/t

a=(0-32)/0.5

a = 64 m/s^2 (decelerating)

F = ma = (0.2 kg)(64 m/s^2)

F = 12.8 N

<span>Hope this answer will be a good h<span>elp for you.</span></span>

8 0
3 years ago
Read 2 more answers
An object accelerates 20.8 m/s2 when a force of 8.9 newtons is applied. What is the mass of the object?
Leona [35]

Answer: 0.43kg

Explanation: a = 20.8m/s^2

                      F = 8.9N

                      m = ?

F = ma

8.9 = 20.8m

m = 8.9/20.8

= 0.43kg

Hope this helped..

7 0
3 years ago
The question is in the attachment!!​
Bingel [31]

Explanation:

|F|= B/2

B/2 = √(A²+B²+2ABcosθ) ------(1)

Since the resultant of A and B is perpendicular to Vector A

tan90°= BSinθ/(A+BCosθ)

(A+BCosθ)=0

Cosθ=-A/B ----(2)

Using equation (1)

B/2 = √(A²+B²+2ABcosθ)

B/2 = √(A²+B²+2AB×-A/B)

B/2=√(A²+B²-2A²)

B/2=√(B²-A²)

B²/4=B²-A²

A²=B²-B²/4

A²=3B²/4

A=√3B/2

Using equation (2)

Cosθ=-A/B

Cosθ=-[√3B/2]/B

Cosθ=-√3/2

θ= cos^-1 (-√3/2)

θ= 150°

7 0
3 years ago
Pls help i have test
Brums [2.3K]

Answer:

c.objectsbin motion tend to stay in motion

Explanation:

hope this helps

8 0
3 years ago
Read 2 more answers
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