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VMariaS [17]
2 years ago
9

While walking past a construction site, a person notices a pipe sticking out of a second floor window with water pouring out. As

the water flows to the ground, it speeds up due to the effect of gravity. How does the diameter of the flowing stream of water change as it descends? Assuming that the flow remains laminar, its diameter decreases. stays the same. increases.
Physics
1 answer:
sukhopar [10]2 years ago
8 0

Answer:

The flow diameter decreases.

Explanation:

From continuity equation,

Q = AV = constant

Where A is the area of the pipe which is proportional to its diameter.

V is the velocity of flow of fluid.

Q is the flow rate.

Let us consider the flow rate through the pipe. Assuming a steady state flow, if the velocity should increase, then the diameter will decrease.

For the flow leaving the pipe and descending to the floor, the flow is accelerated under gravity as it leaves the pipe. This acceleration causes its velocity to increase and consequently causing a reduction in the flow area. The result is the narrowing of the water that flows towards the floor (provided the flow remains laminar).

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Ierofanga [76]
<span>A body has translatory motion if it moves along a: mcqs </span>
8 0
3 years ago
A coil of wire containing N turns is in an external magnetic field that is perpendicular to the plane of the coil and it steadil
krok68 [10]

Answer:

The Resultant Induced Emf in coil is 4∈.

Explanation:

Given that,

A coil of wire containing having N turns in an External magnetic Field that is perpendicular to the plane of the coil which is steadily changing. An Emf (∈) is induced in the coil.

To find :-

find the induced Emf if rate of change of the magnetic field and the number of turns in the coil are Doubled (but nothing else changes).

So,

   Emf induced in the coil represented by formula

                          ∈  =   -N\frac{d\phi}{dt}                                  ...................(1)

                                          Where:

                                                    .   \phi = BAcos\theta     { B is magnetic field }

                                                                                 {A is cross-sectional area}

                                                    .  N = No. of turns in coil.

                                                    .  \frac{d\phi}{dt} = Rate change of induced Emf.

Here,

Considering the case :-

                                    N1 = 2N  &      \frac{d\phi1}{dt} = 2\frac{d\phi}{dt}

Putting these value in the equation (1) and finding the  new emf induced (∈1)

                           

                                      ∈1 =-N1\times\frac{d\phi1}{dt}

                                      ∈1 =-2N\times2\frac{d\phi}{dt}

                                       ∈1 =4 [-N\times\frac{d\phi}{dt}]

                                        ∈1 = 4∈             ...............{from Equation (1)}      

Hence,

The Resultant Induced Emf in coil is 4∈.        

                           

8 0
3 years ago
A flexible shaft consists of a 3 mm diameter steel wire in a flexible hollow tube which imposes a frictional torque of 0.04 N m
Rom4ik [11]

Answer:

2.5m

Explanation:

Torque is defined as the rotational effect of a force on a body.

The torque T for the maximum shear stress is given as 0.1 Nm

Frictional torque is the torque caused by a frictional force

The frictional torque F is given as 0.04 Nm/m

The maximum length of the shaft is thus given as

L = T / F

  = 0.1/0.04

L= 2.5 m

6 0
3 years ago
A woman with a mass of 52.0 kg is standing on the rim of a large disk that is rotating at an angular velocity of 0.470 rev/s abo
Charra [1.4K]

Explanation:

It is given that,

Mass of the woman, m₁ = 52 kg

Angular velocity, \omega=0.47\ rev/s=2.95\ rad/s

Mass of disk, m₂ = 118 kg

Radius of the disk, r = 3.9 m

The moment of inertia of woman which is standing at the rim of a large disk is :

I={m_1r^2}

I={52\times 3.9^2}

I₁ = 790.92 kg-m²

The moment of inertia of of the disk about an axis through its center is given by :

I_2=\dfrac{m_2r^2}{2}

I_2=\dfrac{118\times (3.9)^2}{2}

I₂ =897.39 kg-m²

Total moment of inertia of the system is given by :

I=I_1+I_2

I=790.92+897.39

I = 1688.31 kg-m²

The angular momentum of the system is :

L=I\times \omega

L=1688.31 \times 2.95

L=4980.5\ kg-m^2/s

So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.

8 0
3 years ago
Un casquillo de cobre de 8 kilogramos tiene que calentarse de 25 a 140 grados Celsius con el fin de expandirlo pata que se ajust
uranmaximum [27]

Answer:

354200J

Explanation:

Given parameters:

Mass of copper bushing = 8kg

Initial temperature  = 25°C

Final temperature  = 140°C

Unknown:

Quantity of heat required to heat this mass = ?

Solution:

The amount of heat required to heat mass from one temperature to another is given by;

                  H = m c Δt

where m is the mass

          c  is the specific heat

        Δt is the change in temperature

C is a constant and for copper, its value is 385J/kg°C

 Input the parameters;

            H = 8 x 385 x (140 - 25) = 354200J

8 0
3 years ago
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