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Dmitry [639]
3 years ago
8

An engine manufacturer makes the claim that the engine they have developed will, on each cycle, take 100J of heat out of boiling

water at 100∘C, do mechanical work of 80J, and exhaust 20J of heat at 10∘C. What, if anything, is wrong with this claim?
Physics
1 answer:
Alborosie3 years ago
4 0

Answer:

Explanation:

Intake heat, QH = 100 J

output heat, Qc = 20 J

Work, W = 80 J

TH = 100°C = 373 K

Tc = 10°C = 283 K

TH/ Tc =  373 / 283 = 1.318

QH/Qc = 100 / 20 = 5

for a heat engine, those ratios should be same. so temperature is not correct.

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{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}

\longrightarrow The rate of change of velocity per unit time is called acceleration.

\longrightarrow Its SI unit is m/s².

\huge\boxed{\fcolorbox{blue}{red}{Thank you}}

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