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chubhunter [2.5K]
4 years ago
14

What is the coefficient of the second term of the trinomial?

Mathematics
2 answers:
boyakko [2]4 years ago
7 0

This is the correct answer, I even provided proof from my own test. Hope this helps!

trapecia [35]4 years ago
5 0

(3x+3)^2

(3x+3) * (3x+3)

FOIL

3x*3x +3x*3 +3x*3 +3*3

9x^2 +9x+9x+9

9x^2 +18x+9

B=18

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JulijaS [17]

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BLACKLIVESMATTER!!!!

Step-by-step explanation:

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8 0
3 years ago
Bill drove 871 miles in 13 hours.
wariber [46]

Answer:

536 miles

Step-by-step explanation:

871/13 = 67

67*8 = 536

8 0
3 years ago
Read 2 more answers
An arithmetic sequence with a third term of 8 and a constant difference of 5.
larisa [96]
An arithmetic sequence (a_n) is as follows:

a_1\\a_2=a_1+d\\a_3= a_1+2d\\a_4=a_1+3d,... where a_1 is the first term and d is the constant difference, 

thus, we see that the n'th term of an arithmetic sequence is a_n=a_1+(n-1)d


in our particular case d=5, the third term is 8, so we have:

a_3=8=a_1+2\cdot5\\\\8=a_1+10\\\\a_1=-2


and the general term is a_n=-2+5(n-1),


Answer: first term is -2, n'th term is -2+5(n-1)


8 0
3 years ago
According to the guideline from the Health Department, every over-weight child needs to take a fitness test. Every ten over-weig
nlexa [21]

Answer:

The expected number of children that can pass the fitness test in a test session is 7.5 and the standard deviation is 1.37.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they pass the health test, or they do not. Whether a child can pass the test is independent with the test result of other children. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

The probability for each child to pass the fitness test is 0.75

This means that p = 0.75

10 independent children

This means that n = 10 Find the expectation and standard deviation of the number of children can pass the fitness test in a test session.

E(X) = np = 10*0.75 = 7.5

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.75*0.25} = 1.37

The expected number of children that can pass the fitness test in a test session is 7.5 and the standard deviation is 1.37.

4 0
3 years ago
Betty's breads is trying to calculate its breakeven point. monthly fixed costs are $5,255. the cost of making one loaf of bread,
rosijanka [135]

Fixed Costs ÷ <span>(Price - Variable Costs) = Breakeven Point
</span>

$5,255 ÷  ( 6.00-3.50) = <span>Breakeven Point
</span>$5,255 ÷  ( 2.50) = <span>Breakeven Point
</span><span>Breakeven Point =2102

Check
$3.50 * 2102 = $7357 + $5255 =$12612
$6.00 * 2102 = $12612
$12612 = $12612

</span>








4 0
3 years ago
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