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Dafna1 [17]
3 years ago
14

Given the first three terms of a linear sequence: 3x – 2;x+9; 2x + 5 Determine the value of x.​

Mathematics
2 answers:
Yuliya22 [10]3 years ago
5 0

Answer:

x = 5

Step-by-step explanation:

The difference between consecutive terms will be equal , then

a₂ - a₁ = a₃ - a₂ , that is

x + 9 - (3x - 2) = 2x + 5 - (x + 9) ← distribute parenthesis on both sides

x + 9 - 3x + 2 = 2x + 5 - x - 9 , simplify both sides

- 2x + 11 = x - 4 ( subtract x from both sides )

- 3x + 11 = - 4 ( subtract 11 from both sides )

- 3x = - 15 ( divide both sides by - 3 )

x = 5

AveGali [126]3 years ago
5 0

Answer:

x = 5

Step-by-step explanation:

Each new term is 1 greater than the previous term.  Therefore:

x + 9 = (3x - 2) + 1                   Equivalent to x + 9 = 3x - 2 + 1, or:

                                                                       9 + 2 - 1 = 2x, or 2x = 10

                                                Thus, x = 5

Check by substituting 5 for x as indicated:

3x - 2 becomes 13 (which means the next term must be 14)

x + 9 becomes 14, and

2x + 5 becomes 15

and these consecutive sequence terms are {13, 14, 15}

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(2/3q – 3/4) and (–1/6q – r) What is the coefficient of q in the sum of these two expressions?
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Answer:

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Step-by-step explanation:

Given expressions are \frac {2}{3q}-\frac {3}{4} and  \frac{-1}{6q}-r

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