So 5.10 is 100% and 0.57 is x%
percent means parts out of 100
5.10/100%=0.57/x% since they are equal (exg 2/4=3/6)
5.10/100=0.57/x
multipy both sides by x/0.57 to clear fraciton
(5.1x)/57=1
multiply both sides by 57 to get rid of the denomeator (bottom number
5.1x=57
divde both sides by 5.1
x=11.1765
increase of 11.2%
( an easy way is (0.57/5.1) times 100)
Answer:
Step-by-step explanation:
Given that you drew all possible random samples of size 1,000 from the population of LSAT test takers
Plotted the values of the mean from each sample
As per central limit theorem, we find that for sample sizes of minimum 30, the means of all such samples randomly drawn would follow a bell shaped curve with normal distribution irrespective of the original distribution of the population.
Hence here answer is yes, this would be a normal distribution as per central limit theorem.
Answer: She will need about 15 bananas to feed 250 people that will be at the reunion.
Step-by-step explanation:
Let be "x" the number of bananas Stewart will need to feed 250 people that will be at the reunion.
According to the infomation provided in the exercise, we know that she needs 1.5 bananas per dish of pudding and one dish of pudding can feed 25 people.
Knowing this, we can set up the following proportion:
Finally, we must solve for "x":
Therefore, she will need about 15 bananas to feed 250 people that will be at the reunion.
Answer:
ok
Step-by-step explanation:
62 multiplied by 3 is 186
Add on 31 for the half hour
and you get 217
