1/4 of the school is boys
1/2 of 1/4 is 1/8
2/3 of 3/4 is 5/12
1/4 of boys and 5/12 of girls are there
330 people are at the event
If 3/4 of the school is there, then there are 440 people in school
The distance from the sun is option 2 5.59 astronomical units.
Step-by-step explanation:
Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.
Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power
is on the variable we need to find so we multiply both the sides by an exponential power of
to be able to calculate 'a'.
P =
,
=
,
= a,
= a = 5.58533 astronomical units.
Rounding it over to nearest hundredth we get 5.59 astronomical units.
If the given expression is simplified we get a. -4x² - 3x + 2.
Explanation:
- The numerator has three terms while the denominator only has one term. We divide the numerator terms each separately with the denominator term.
- So 8x³ + 6x² - 4x / -2x becomes (8x³ / -2x) + (6x² / -2x) + (- 4x/ -2x).
- The simplification of the first term; 8 / -2 = -4, x³ / x = x². So the first term is -4x².
- The simplification of the second term; 6 / -2 = -3, x² / x = x. So the second term is -3x.
- The simplification of the third term; -4 / -2 = 2, x / x = 1. So the third term is 2.
- Adding all the terms we get -4x² - 3x + 2. This is the option a.
Answer:
10.8
Step-by-step explanation:
E has increased by a factor of 18/10 = 1.8, so G will increase by that factor. The corresponding value of G is ...
6 × 1.8 = 10.8 = G
__
If you like, you can write an equation relating G to E:
E = kG
10 = k(6)
k = 10/6 = 5/3
Now for E = 18, we have ...
18 = (5/3)G
18(3/5) = G = 10.8
The median, because the data is not symmetric and there are outliers is the data is not symmetric and there are outliers.
The median of the data set is 8 cakes, while the average is 7.5.
However, 21 of the 31 chefs, or roughly 2/3, made 8 or more cakes. This makes the median a better center for this data, since the data is clearly skewed. The four chefs that made 1 cake each brings the average down, skewing the mean and making the median a better representation of the data.