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babunello [35]
3 years ago
14

1. The two qualities used to describe winds are________ and speed. 2. a local wing that blows during the day from an ocean towar

d land is a(n)_______. 3. the increase in cooling that wind can cause is called the ______. 4. Temperature differences between the equator and poles produce _____ currents. Help me with may homework.
Chemistry
1 answer:
Mazyrski [523]3 years ago
4 0
<span>1. The two qualities used to describe winds are direction and speed.
2. a local wind that blows during the day from an ocean toward land is a(n) sea breeze.
3. The increase in cooling that wind can cause is called the wind-chill factor.
4. Temperature differences between the equator and poles produce convection currents.
A movement that is parallel to Earth's Surface is called wind and a local wind is that wind that blows over a short distance.</span>
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Which of the following would be expected to have the highest viscosity? CH3CH2OH, HOCH2OH, CH3CH2CH3
zaharov [31]

Answer: Out of the given options HOCH_{2}OH is expected to have the highest viscosity.

Explanation:

The resistance occurred in the flow of a liquid substance is called viscosity.

More stronger is the intermolecular forces present in a substance more will be its resistance in its flow. Hence, more will be its viscosity.

For example,  HOCH_{2}OH has strong intermolecular hydrogen bonding than the one's present in CH_{3}CH_{2}OH and CH_{3}CH_{2}CH_{3}. This is because two-OH groups are present over here.

Thus, we can conclude that out of the given options HOCH_{2}OH is expected to have the highest viscosity.

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2 years ago
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
An 8 oz. bottle of energy drink contains 6.0 g of protein, 2.0 g of fat, and 16.3 g of carbohydrate. The fuel value of this ener
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<u>Answer:</u> The correct option is d) 460 kJ

<u>Explanation:</u>

We are given:

Content of fat in energy drink = 2.0 g

Content of protein in energy drink = 6.0 g

Content of carbohydrate in energy drink = 16.3 g

Also,

The fuel value of fat = 38 kJ/g

The fuel value of protein = 17 kJ/g

The fuel value of carbohydrate = 17 kJ/g

So, the fuel value of the energy drink will be:

Total fuel value = (2.0g\times 38 kJ/g)+(6.0g\times 17 kJ/g)+(16.3g\times 17 kJ/g)

Total fuel value = [76+102+277]=460kJ

Hence, the correct option is d) 460 kJ

4 0
3 years ago
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