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11Alexandr11 [23.1K]
4 years ago
12

Sulfuric acid reacts with aqueous sodium hydroxide to produce aqueous sodium sulfate and liquid water. Which is the correct bala

nced chemical equation for this reaction description?
Chemistry
1 answer:
Bogdan [553]4 years ago
4 0

Answer:

Balanced reaction is:  H₂SO₄ (aq) + 2NaOH (aq) → Na₂SO₄ (aq) + 2H₂O (l)

Explanation:

We determine the reactants:

H₂SO₄ → Sulfuric acid

NaOH → Sodium hydroxide

When a strong acid and a strong base react each other, it is produced water and a determined salt. This is a reaction of <em><u>neutralization</u></em>

We dissociate the reactants:

H₂SO₄ → 2H⁺ + SO₄⁻²

NaOH →  Na⁺ + OH⁻

2H⁺ + 2OH⁻ → 2H₂O

2Na⁺ + SO₄⁻²  → Na₂SO₄

Balanced reaction is:  H₂SO₄ (aq) + 2NaOH (aq) → Na₂SO₄ (aq) + 2H₂O (l)

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You observe mothballs disappearing in cabinets. What do you think is the reason for this? Do all substances behave like mothball
cricket20 [7]

Answer: Mothballs have weak intermolecular forces.

No all substances do not behave like mothballs at normal conditions. Example: benzene , chloroform

Explanation:

Sublimation is a process of converting a substance from solid state to gaseous state without the formation of liquid at constant temperature.

A substance which undergoes sublimation is called as sublimating substance.

As mothballs is made of napthalene which has weak inter molecular forces of attraction between its molecules, it directly sublimes into gaseous state without leaving any residue and is called as a sublimating substance.

Not all substances behave like mothballs at normal conditions. Example: benzene , chloroform

8 0
3 years ago
A reaction between substances Y and Z is
Anuta_ua [19.1K]

Answer : The value of activation energy for this reaction is 108.318 kJ/mol

Explanation :

The Arrhenius equation is written as:

K=A\times e^{\frac{-Ea}{RT}}

Taking logarithm on both the sides, we get:

\ln k=-\frac{Ea}{RT}+\ln A             ............(1)

where,

k = rate constant  = 2.95\times 10^{-3}L/mol.s

Ea = activation energy  = ?

T = temperature = 435 K

R = gas constant  = 8.314 J/K.mole

A = pre-exponential factor  = 3.00\times 10^{+10}L/mol.s

Now we have to calculate the value of rate constant by putting the given values in equation 1, we get:

\ln (2.95\times 10^{-3}L/mol.s)=-\frac{Ea}{8.314J/K.mol\times 435K}+\ln (3.00\times 10^{10}L/mol.s)

Ea=108318.365J/mol=108.318kJ/mol

Therefore, the value of activation energy for this reaction is 108.318 kJ/mol

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3 years ago
Need help with this question
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What question? Lhh this is hilarious.
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