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ElenaW [278]
2 years ago
15

423.3 mL of gas is at 49.2 C. It is compressed to a volume of 79 mL. What is the new temperture. Express your answer in Kelvin.

Chemistry
1 answer:
zzz [600]2 years ago
8 0

Answer: 60.1K

Explanation:

Initial volume of gas V1 = 423.3mL

Initial temperature T1 = 49.2°C

Convert temperature in Celsius to Kelvin

( 49.2°C + 273 = 322.2K)

Final temperature T2 = ?

Final volume V2 = 79mL

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

423.3mL/322.2 = 79mL/T2

To get the value of T2, cross multiply

423.3mL x T2 = 322.2K x 79mL

423.3mL x T2 = 25453.8

T2 = (25453.8/423.3mL)

T2 = 60.1K

Thus, the new temperature of the gas is 60.1K

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5 0
2 years ago
How much heat is lost when 575 grams molten iron at 1825 k becomes solid iron at 293 k? The melting point or iron is 1811 k.​
Galina-37 [17]

Answer:

146 kJ  

Explanation:

There are two heat flows in this question.  

Heat lost on cooling + heat lost on solidifying = 0  

                 q₁              +                 q₂                   = 0  

              mCΔT          +             nΔHsol              = 0  

Data:  

       m = 575 g  

       C = 0.449 J·K⁻¹g⁻¹  

    T_i = 1825 K  

    T_f = 1811 K  

ΔHsol = -13.8 kJ·mol⁻¹  

Calculations:  

(a) Heat lost on cooling  

ΔT = T_f - T_i = 1811 K - 1825 K = -14 K  

q₁ = mCΔT = 575 g × 0.449 J·K⁻¹g⁻¹ × (-14 K) = -361 J = -3.61 kJ  

(b) Heat lost on solidifying  

n = \text{575 g} \times \dfrac{\text{1 mol}}{\text{55.84 g}} = \text{10.30 mol}\\\\q_{2} = n\Delta_{\text{sol}}H = \text{10.30 mol} \times \dfrac{\text{-13.8 kJ}}{\text{1 mol}}= \text{-142.1 kJ}

(c) Total heat lost  

q = q₁ + q₂ = -3.61 kJ - 142.1 kJ = -146 kJ  

The heat lost was 146 kJ.

 

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<u><em>Answer:</em></u>

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