Answer:
Alan: 200 m/min
Brian: 150 m/min
Step-by-step explanation:
Given : Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same point. Alan races around the track in 45 seconds before Brian does and overtakes him every 9 minutes.
To find : What are their rates, in meters per minute?
Solution :
Let n represent the number of laps that Alan completes in 9 minutes.
Then n-1 is the number of laps Brian completes.
45 seconds = 3/4 minutes.
The difference in their lap times in minutes per lap is

Solving the equation we get,








Neglecting n=-3
So, n=4
Then Alan's speed in m/min is



Brian completes 3 laps in that 9-minute time, so his rate is


Therefore, Alan: 200 m/min
Brian: 150 m/min
Answer: Frequencies .
Step-by-step explanation:
In statistics theory the chi-square test statistic is calculated by considering each cell and the expected frequency is subtracted from the observed frequency after that the difference is squared, and the total is divided by the expected frequency. This is highlight that the key focus of the chi-square test is the frequencies .
Answer:
10
Step-by-step explanation:
7+15/5
We don’t know the number of employees remaining at the company.
We don’t know the total number of employees remaining at the company.
The classification consists of gender, division, and employment type.
It doesn’t matter what order those attributes come in. A person who is male, age group 6, and employment type 10 has the same classification as someone who is of employment type 6, male, and age group10.
Therefore since order does not matter it is a combination question.
Assuming only two genders are allowed (you didn’t say and some people think there are about 10 of them)
It is either 120 (2 times 6 times 10) or "None of the above" if you believe there are more than 2 genders.
2×6×10=120
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Answer: 0.14
Step-by-step explanation:
1) Find the total #of seniors. To do this add up 25+5+5 = 35.
2)Since we know the number of seniors that work just do 5/35. This simplifies to 0.14 rounded to the nearest hundreth.