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hodyreva [135]
4 years ago
5

tle="x + y + {x}^{2} - {y}^{2} " alt="x + y + {x}^{2} - {y}^{2} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Alexus [3.1K]4 years ago
5 0

Answer:

(x + y)(1 + x - y)

Step-by-step explanation:

x + y + x² - y²

(x + y) + (x - y)(x + y)

[ Using a²-b² = (a-b)(a+b) ]

Taking (x + y) common

(x + y)(1 + x - y)

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Which choices are equivalent to the quotient below? Check all that apply.<br><br> √75/√15
Lubov Fominskaja [6]

The value of the fraction is \rm \sqrt{5} , Option D is the correct answer.

The complete question is

Which choices are equivalent to the quotient below? Check all that apply √75/√15 A. 5 B. √25/√5 C. 15/3 D. √5 E. √3 F. √15/√3

<h3>What is a Fraction ?</h3>

When a number is represented by p/q , where q ≠ 0 is called a fraction.

The given fraction is

\rm \dfrac{\sqrt{75}}{\sqrt {15}}\\\\\\\\dfrac{\sqrt{3*5 *5}}{\sqrt {3*5}}\\\\\\\sqrt{5}\\

Therefore , the value of the fraction is \rm \sqrt{5} , Option D is the correct answer.

To know more about Fraction

brainly.com/question/10354322

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6 0
2 years ago
Rewrite the fractions 3/4 and 5/14 as fractions with a least common denominator?
andriy [413]

Answer:

The least common denominator would be 28.

Mutiply by 7 for 3/4.

Mutiply by 2 for 5/14.

3(7)/4(7)= 21/28, 5(2)/14(2)= 10/28

4 0
3 years ago
Read 2 more answers
....Math I need help
Brilliant_brown [7]
M<FIB = 90 -  (4x+3)
m<FIB = 87 - 4x

---------------------
m<HFG = 90 - (5x + 4)
m<HFG = 86 - 5x

-------------------------------
<BCF = 180 - (<CBF + <CFB)
<CBF  = 10x + 3
<CFB =90 - <CFD
but <CFD = <HFG = 86 - 5x (vertical angles)

<CFB =90 -(86 - 5x) = 4 + 5x

<BCF = 180 - (10x + 3  + 4 + 5x)
<BCF = 180 - (15x + 7)
<BCF = = 173 - 15x

3 0
3 years ago
What should be measured to calculate the average rate at which the water in a cup cools?
tekilochka [14]
The temperature of the water should be measured.
5 0
3 years ago
patricia says that it's more appropriate to use the method of factoring than extracting square roots in solving 4x2^-9=0. do you
zavuch27 [327]
1^{o} \\  \\ 4x^{2}-9=0 \\  \\ (2x-3)(2x+3)=0 \\  \\ 2x-3=0 \ \vee \ 2x+3=0 \\  \\ 2x=3 \ \vee \ 2x=-3 \\  \\ x= \frac{3}{2}  \ \vee \ x=- \frac{3}{2}  \\  \\ 2^{o} \\  \\ 4x^{2}-9=0 \\  \\ 4x^{2}=9 \\  \\ x^{2}= \frac{9}{4}  \\  \\ x= \sqrt{ \frac{9}{4} } \ \vee \ -\sqrt{ \frac{9}{4} }  \\  \\ x= \frac{3}{2} \ \vee \ x=- \frac{3}{2}  \\  \\ 3^{o} \\  \\ 4x^{2}-9=0 \\  \\ \Delta=0^{2}-4*4*(-9)=144 \\  \\  \sqrt{\Delta}  =12 \\  \\ x_{1}= \frac{0+12}{8} = \frac{3}{2}

x_{2}= \frac{0-12}{8} =- \frac{3}{2}
8 0
4 years ago
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