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professor190 [17]
4 years ago
9

Jake performed an experiment to find out which type of chocolate melts the fastest, milk chocolate or dark chocolate. He tested

the melting, and second, a 15 different randomly selected brands of each type of chocolate in a double boiler set to 90°. What is most likely true about the melting times of these two types of chocolates? Jake performed an experiment to find out which type of chocolate melts the fastest, milk chocolate or dark chocolate. He tested the melting, in seconds, a 15 different randomly selected brands of each type of chocolate in a double boiler set to 90°. What is most likely true about the melting times of these two types of chocolates?

Mathematics
1 answer:
lutik1710 [3]4 years ago
4 0

Answer:

Please see attached image for full question

"After 64 seconds, ABOUT HALF of the brands of milk chocolate are LIKELY  to melt and NONE of the brands of Dark Chocolate are likely to melt"

Step-by-step explanation:

The right answer is

"After 64 seconds, ABOUT HALF of the brands of milk chocolate are LIKELY  to melt and NONE of the brands of Dark Chocolate are likely to melt"

We can easily check this solution by seeing the time it took for each chocolate to melt in the attached picture.

After 64 seconds have passed, half of the brands of milk chocolate had already melted, but the dark chocolate time starts after 200s

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Answer:

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Step-by-step explanation:

890cm \times 2891cm = 2572990 {cm}^{2}

890 + 66 = 956

956cm \times 2891cm = 2763796 {cm}^{2}

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Answer:

1. 3/32

2. 3/8

3. 1/20

Step-by-step explanation:

\frac{1}{8} * \frac{3}{4} = \frac{3}{32}

\frac{2}{4} * \frac{3}{4} = \frac{6}{16}\\\\\\frac{6}{16} = \frac{3}{8}

\frac{1}{10} * \frac{4}{8} = \frac{4}{80}\\\\\frac{4}{80}  = \frac{1}{20}

6 0
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Please help I need to finish my winter packet and no one is answering my questions
Damm [24]

Answer:

\sqrt[7]{x^{4}}

(x^{\frac{1}{7}})^{4}

(\sqrt[7]{x})^{4}

Step-by-step explanation:

we have

x^{\frac{4}{7}}

Remember the properties

\sqrt[n]{a^{m}}=a^{\frac{m}{n}}

(a^m)^{n}=a^{m*n}

so

<u><em>Verify each case</em></u>

Part 1) we have

\sqrt[4]{x^{7}}

we know that

\sqrt[4]{x^{7}}=x^{\frac{7}{4}}

Compare with the given expression

x^{\frac{7}{4}} \neq x^{\frac{4}{7}}

Part 2) we have

\sqrt[7]{x^{4}}

we know that

\sqrt[7]{x^{4}}=x^{\frac{4}{7}}

Compare with the given expression

x^{\frac{4}{7}} = x^{\frac{4}{7}}

therefore

Is equivalent to the given expression

Part 3) we have

(x^{\frac{1}{7}})^{4}

we know that

(x^{\frac{1}{7}})^{4}=x^{\frac{4}{7}}

Compare with the given expression

x^{\frac{4}{7}} = x^{\frac{4}{7}}

therefore

Is equivalent to the given expression

Part 4) we have

(x^{\frac{1}{4}})^{7}                      

we know that

(x^{\frac{1}{4}})^{7}=x^{\frac{7}{4}}

Compare with the given expression

x^{\frac{7}{4}} \neq x^{\frac{4}{7}}

Part 5) we have

(\sqrt[4]{x})^{7}

we know that

(\sqrt[4]{x})^{7}=(x^{\frac{1}{4}})^{7}=x^{\frac{7}{4}}

Compare with the given expression

x^{\frac{7}{4}} \neq x^{\frac{4}{7}}

Part 6) we have

(\sqrt[7]{x})^{4}

we know that

(\sqrt[7]{x})^{4}=(x^{\frac{1}{7}})^{4}=x^{\frac{4}{7}}

Compare with the given expression

x^{\frac{4}{7}} = x^{\frac{4}{7}}

therefore

Is equivalent to the given expression

7 0
3 years ago
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