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4 years ago

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heated to a final state where the pressure is 6 bar and the temperature is 160°C. While the ammonia is heated, its pressure vari

es linearly with specific volume. For the ammonia, determine the work and heat transfer, each in kJ/kg.

1 answer:

malfutka [58]4 years ago

3 0

Answer:

W = 62.81kJ/kg

Q = 1222.1kJ/kg.

Explanation:

See attachment below.

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An oscillator consists of a block of mass 0.373 kg connected to a spring. When set into oscillation with amplitude 33 cm, the os

aniked [119]

Answer:

(a) T = 0.412s

(b) f = 2.42Hz

(c) w = 15.25 rad/s

(d) k = 86.75N/m

(e) vmax = 5.03 m/s

Explanation:

Given information:

m: mass of the block = 0.373kg

A: amplitude of oscillation = 22cm = 0.22m

T: period of oscillation = 0.412s

(a) The period is the time of one complete oscillation = 0.412s

The period is 0.412s

(b) The frequency is calculated by using the following formula:

$f=\frac{1}{T}=\frac{1}{0.412s}=2.42Hz$

The frequency is 2.42 Hz

(c) The angular frequency is:

$\omega=2\pi f=2\pi (2.42Hz)=15.25\frac{rad}{s}$

The angular frequency is 15.25 rad/s

(d) The spring constant is calculated by solving the following equation for k:

$\omega=\sqrt{\frac{k}{m}}\\\\k=m\omega^2=(0.373kg)(15.25rad/s)^2=86.75\frac{N}{m}$

The spring constant is 86.75N/m

(e) The maximum speed is:

$v_{max}=\omega A=(15.25rad/s)(0.33m)=5.03\frac{m}{s}$

(f) The maximum force applied by the spring if for the maximum elongation, that is, the amplitude:

$F=kA=(86.75N/m)(0.2m)=17.35N$

The maximum force that the spring exerts on the block is 17.35N

3 0

4 years ago

Electric field lines can never cross.

svetoff [14.1K]

Crossed electric field lines indicate A) a field pointing in two directions

4 0

3 years ago

Read 2 more answers

An argon ion laser puts out 5.0 W of continuous power at a wavelength of 532 nm. The diameter of the laser beam is 5.5 mm. If th

stepan [7]

Answer:

Number of photons travel through pin hole= $6.4*10^{17}$

Explanation:

First we will calculate the energy of single photon using below formula:

$E=\frac{h*c}{λ}$

Where :

h is plank's constant with value $6.626*10^{-34} J.s$

c is the speed of light whch is $3*10^{8}$

λ is the wave length = 532nm

$E=\frac{6.6268*10^{-34}* 3*10^{8}}{532nm}$

E= $3.73*10^{-19}$ J

Number of photons emitted per second:

$\frac{5J/s}{1 photon/3.73*10^{-19} }$

Number of photons emitted per second= $1.34*10^{19} photons/s$

$\frac{A-hole}{A-beam}$ = $\frac{\frac{pie*d-hole^2}{4}}{\frac{pie*d-beam^2}{4} }$

Where:

A-hole is area of hole

A-beam is area of beam

d-hole is diameter of hole

d-beam is diameter if beam

$\frac{A-hole}{A-beam}$ = $\frac{d-hole^2}{d-beam^2}$

$\frac{Ahole}{A-beam}$ = $\frac{1.22^2}{5.5^2}$

$\frac{A-hole}{A-beam}$ = $\frac{144}{3025}$

Number of photons travel through pin hole= $1.34*10^{19} *\frac{144}{3025}$

Number of photons travel through pin hole= $6.4*10^{17}$

7 0

3 years ago

You are reshelving books in a library. You lift a book from the floor to the top shelf. The kinetic energy of the book on the fl

lisabon 2012 [21]

Answer:

No, the theorem is not violated

Explanation:

No, it is not violated because the work done by gravitational force must also be taken into account. The force to lift the book at constant speed is the same as the gravitational force, i.e. the work done by the gravitational force (weight) is equal in magnitude but negative to the work done by the person to lift the book. (The work done by gravity is negative because displacement and weight have opposite directions).

So if we apply the theorem the work and kinetic energy, we have that the total work done in the book (work of the person plus the gravitational work) is equal to zero, and it is equal to the change of the kinetic energy. The theorem is fulfilled

7 0

3 years ago

To understand the origin of the torque on a current loop due to the magnetic forces on the current-carrying wires.

Law Incorporation [45]

Answer:

The torque is $\tau = B * m sin(\phi )$

Explanation:

Generally when current flow through a rectangular loop the magnetic dipole generated we can denote this as $\vec m$

Here k is the length of the side of one side of the rectangular loop

Now when this loop is place in a magnetic field, the torque it experience is mathematically represented as

$\vec \tau = \vec B \ X \ \vec m$

Here X stands for cross - product

From the question we are told that the angle between the vector ( $\vec m$ )perpendicular to the plane of the coil and magnetic field(B) as $\phi$

So

=> $\tau = B * m sin(\phi )$

3 0

4 years ago