All categories

4 years ago

true or false Both the large loose rocks and the small loose rocks used to be part of earth's solid rock layer

1 answer:

8 0

Hello Micu212006

Question: <span> Both the large loose rocks and the small loose rocks used to be part of earth's solid rock layer
</span><span>
Answer: True

Hope This Helps!
-Chris </span>

You might be interested in

A small, single engine airplane is about to take off. The airplane becomes airborne, when its speed reaches 161.0 kmph. The cond

lukranit [14]

Answer:

384.6 m

Explanation:

The length of the runway airport should be long enough to accommodate the aircraft during its acceleration from rest to 161 km/h at rate of 2.6 m/s. We can use the following equation of motion to solve for this:

$v^2 - v_0^2 = 2a\Delta s$

where v0 = 0 m/s is the initial velocity of the airplane when it start accelerating, v = 161 km/h = 161*1000*(1/60)(1/60) = 44.72 m/s is the airborn speed, a = 2.6 m/s2 is the acceleration, and $\Delta s$ is the distance of the runway, which we care looking for

$44.72^2 - 0 = 2*2.6\Delta s$

$\Delta s = 44.72^2/(2*2.6) = 384.6 m$

5 0

4 years ago

A Ferris wheel has a radius of 25 feet. The wheel is rotating at two revolutions per minute. Find the linear speed, in feet per

svet-max [94.6K]

Linear velocity and angular velocity are related by the formula:
v = ωr

ω = n2πr/t, where n is the number of rotations, t is the time taken, r is the radius.
ω = 2 x 2π x 25/1
ω = 100π

v = 100π x 25
= 2500π feet per minute

8 0

4 years ago

If a power utility were able to replace an existing 500 kV transmission line with one operating at 1 MV, it would change the amo

mestny [16]

Answer:

It would change the amount of heat produced in the transmission line to four times the previous value.

Explanation:

Given;

initial voltage in the transmission line, V₁ = 500 kV = 500,000 V

Final voltage in the transmission line, V₂ = 1 MV = 1,000,000

The power lost in the transmission line due to heat is given by;

$P = \frac{V^2}{R}$

Power lost in the first wire;

$P_1 = \frac{V_1^2}{R}$

$R = \frac{V_1^2}{P_1}$

Power lost in the second wire

$P_2 = \frac{V_2^2}{R}\\\\ R = \frac{V_2^2}{P_2}$

Keeping the resistance constant, we will have the following equation;

$\frac{V_2^2}{P_2} = \frac{V_1^2}{P_1} \\\\P_2 = \frac{V_2^2P_1}{V_1^2}\\\\$

$P_2 = \frac{(1,000,000)^2P_1}{(500,000)^2}\\\\P_2 =4P_1$

Therefore, it would change the amount of heat produced in the transmission line to four times the previous value.

8 0

3 years ago

Suppose you take a piece of hard wax from an unlit candle. After you roll the wax between your fingers for a while, it becomes s

romanna [79]

Answer:

An amorphous solid does not have a definite melting point; instead, it melts gradually over a range of temperatures, because the bonds do not break all at once. This means an amorphous solid will melt into a soft, malleable state (think candle wax or molten glass) before turning completely into a liquid.

Explanation:

Hope this helps

May I get braineist pls?

5 0

3 years ago

Why will a set of stars appear at a different angle to us at different times of the year?

iogann1982 [59]

A set of stars will appear at a different angle to us at different times of the year because of the Earth's orbit around the sun. As it orbits around the sun, the parallax of the stars change.

5 0

3 years ago

Read 2 more answers