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Jobisdone [24]
4 years ago
13

true or false Both the large loose rocks and the small loose rocks used to be part of earth's solid rock layer

Physics
1 answer:
salantis [7]4 years ago
8 0
Hello Micu212006 


Question: <span> Both the large loose rocks and the small loose rocks used to be part of earth's solid rock layer
</span><span>
Answer: True


Hope This Helps!
-Chris </span>
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A small, single engine airplane is about to take off. The airplane becomes airborne, when its speed reaches 161.0 kmph. The cond
lukranit [14]

Answer:

384.6 m

Explanation:

The length of the runway airport should be long enough to accommodate the aircraft during its acceleration from rest to 161 km/h at rate of 2.6 m/s. We can use the following equation of motion to solve for this:

v^2 - v_0^2 = 2a\Delta s

where v0 = 0 m/s is the initial velocity of the airplane when it start accelerating, v = 161 km/h = 161*1000*(1/60)(1/60) = 44.72 m/s is the airborn speed, a = 2.6 m/s2 is the acceleration, and \Delta s is the distance of the runway, which we care looking for

44.72^2 - 0 = 2*2.6\Delta s

\Delta s = 44.72^2/(2*2.6) = 384.6 m

5 0
4 years ago
A Ferris wheel has a radius of 25 feet. The wheel is rotating at two revolutions per minute. Find the linear speed, in feet per
svet-max [94.6K]
Linear velocity and angular velocity are related by the formula:
v = ωr

ω = n2πr/t, where n is the number of rotations, t is the time taken, r is the radius.
ω = 2 x 2π x 25/1
ω = 100π

v = 100π x 25
= 2500π feet per minute
8 0
4 years ago
If a power utility were able to replace an existing 500 kV transmission line with one operating at 1 MV, it would change the amo
mestny [16]

Answer:

It would change the amount of heat produced in the transmission line to four times the previous value.

Explanation:

Given;

initial voltage in the transmission line, V₁ = 500 kV = 500,000 V

Final voltage in the transmission line, V₂ = 1 MV = 1,000,000

The power lost in the transmission line due to heat is given by;

P = \frac{V^2}{R}

Power lost in the first wire;

P_1 = \frac{V_1^2}{R}

R = \frac{V_1^2}{P_1}

Power lost in the second wire

P_2 = \frac{V_2^2}{R}\\\\ R = \frac{V_2^2}{P_2}

Keeping the resistance constant, we will have the following equation;

\frac{V_2^2}{P_2} = \frac{V_1^2}{P_1} \\\\P_2 = \frac{V_2^2P_1}{V_1^2}\\\\

P_2 = \frac{(1,000,000)^2P_1}{(500,000)^2}\\\\P_2 =4P_1

Therefore, it would change the amount of heat produced in the transmission line to four times the previous value.

8 0
3 years ago
Suppose you take a piece of hard wax from an unlit candle. After you roll the wax between your fingers for a while, it becomes s
romanna [79]

Answer:

An amorphous solid does not have a definite melting point; instead, it melts gradually over a range of temperatures, because the bonds do not break all at once. This means an amorphous solid will melt into a soft, malleable state (think candle wax or molten glass) before turning completely into a liquid.

Explanation:

Hope this helps

May I get braineist pls?

5 0
3 years ago
Why will a set of stars appear at a different angle to us at different times of the year?
iogann1982 [59]
A set of stars will appear at a different angle to us at different times of the year because of the Earth's orbit around the sun. As it orbits around the sun, the parallax of the stars change.
5 0
3 years ago
Read 2 more answers
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