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2 years ago

HELP ME PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ

Mathematics

1 answer:

Svet_ta [14]2 years ago

3 0

1. Is correct
2. x^2 - 12
3. 2 / (a-1)

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Find the value of x.

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$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

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$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

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3 years ago

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4x + 3y = 12
3y = -4x + 12
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the x intercept (where the line crosses the x axis) can be found by subbing in 0 for y in the original equation or the slope intercept equation, and solving for x.
4x + 3(0) = 12
4x = 12
x = 12/4 = 3....so the x intercept is (3,0)

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