i need to help write the equation in vertex form for the parabola with vertex at ( 2,-1) and y - intercept 5
1 answer:
Answer: y= 5/2(x-2)^2 - 1
Step-by-step explanation:
y=a(x-2)^2 - 5
5=a(0-2)^2 - 5
10=a(-2)^2
10=a4
a=10/4 or 5/2
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= 2xy(x^2 + 9)- 10y(x^2 + 9)
= (x^2 + 9)(2xy - 10y)
= (x^2 + 9) 2y(x - 5)
= 2y (x^2 + 9) (x - 5)
Answer:
x = 2
Step-by-step explanation:
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Step-by-step explanation:
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