Question

Find the equation of the line that passes through (1,6) and (3,10).

Answer 1

Answer:

m = (y2 - y1) / (x2 - x1) = (10 - 6) / (3 - 1) = 2    slope of line

y = m x + b standard form of straight line

y = 2 x + b      where b is the intercept at x = 0

b = y - 2 x

b = 6 - 2 = 4    from our first equation

Also, b = 10 - 6 = 4       check from second equation

y = 2 x + 4    is our equation

Check if y = 6 and x = 1 then

y = 2 * 1  + 4 = 6   verifying the first point given