Answer:
160
Step-by-step explanation:
Angle ABE is a 180 as ABE forms a line
so angle ABC + ANGLE CBE = 180
x + 20 = 180
x = 180-20
= 160
I hope im right!!
answer is attached below with full explanation
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.
Answer:
2+n=-6
Step-by-step explanation:
To simplify n
n=-8
Answer:
-(1/3)x+1>y
2x-3≥y
If x<12/7 then 2x-3≥y
and if x≥12/7 then -(1/3)x+1>y