Harold paid $ 16,632 and $ 38,808 for each of the boats.
Since Harold, a marina manager, purchased two boats, and he then sold the boats, the first at a profit of 40% and the second at a profit of 60%, and the total profit on the sale of the two boats was 54 % and $ 88 704 was the total selling price of the two boat, to determine what did Harold originally pay for each of the two boats the following calculation must be performed:
- 55 x 0.6 + 45 x 0.4 = 51
- 65 x 0.6 + 35 x 0.4 = 53
- 70 x 0.6 + 35 x 0.4 = 54
- 88,704 x 0.7 = 62,092.80
- 160 = 62,092.80
- 100 = X
- 100 x 62,092.80 / 160 = X
- 38.808 = X
- 88,704 x 0.3 = 26,611.20
- 140 = 26,611.20
- 100 = X
- 100 x 26,611.20 / 160 = X
- 16,632 = X
Therefore, Harold paid $ 16,632 and $ 38,808 for each of the boats.
Learn more in brainly.com/question/21446500
(-16+12)/(-4+2)= (-4)/(-2)= 2
You can multiply or divide one equation so that it has a variable with a coefficient opposite of the other equation.
Example:
A) 2x + 3y = 6
B) 4x +2y = 20
Notice that neither equation has a "1" or "-1"
Let's multiply Equation A) by -2
A) -4x -6y = -12 Then add it to B)
B) 4x +2y = 20
-4y = 8
y= -2
A) 2x + 3*-2 = 6
2x = 12
x = 6
Answer:r=7
Step-by-step explanation:
because im stupid
