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Karo-lina-s [1.5K]
2 years ago
14

The picture says all,,

Mathematics
1 answer:
mixas84 [53]2 years ago
5 0
1/3(9)(10) = 30in^2
Hope it helps, you just have to plug in the values into formula given
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Help thank you<br> Xxxxxxx
enyata [817]
The answer to this is C. I hope this helps you out.
5 0
2 years ago
Read 2 more answers
Learning Theory In a typing class,the averege number N of words per minutes typed after t weeks of lessons can be modeled by N =
Jet001 [13]

Answer:

a) N(t=10) = \frac{95}{1+8.5 e^{-0.12(10)}}= \frac{95}{1+ 8.5 e^{-1.2}} = 26.684

b) N(t=20) = \frac{95}{1+8.5 e^{-0.12(20)}}= \frac{95}{1+ 8.5 e^{-2.4}} = 53.639

c) 70 =\frac{95}{1+8.5 e^{-0.12t}}

1+ 8.5 e^{-0.12t} = \frac{95}{70}= \frac{19}{14}

8.5 e^{-0.12t} = \frac{19}{14}-1= \frac{5}{14}

e^{-0.12t} = \frac{\frac{5}{14}}{8.5}= \frac{5}{119}

ln e^{-0.12t} = ln (\frac{5}{119})

-0.12 t = ln(\frac{5}{119})

t = \frac{ln(\frac{5}{119})}{-0.12} = 26.414 weeks

d) If we find the limit when t tend to infinity for the function we have this:

lim_{t \to \infty} \frac{95}{1+8.5 e^{-0.12t}} = 95

So then the number of words per minute have a limit and is 95 as t increases without bound.

Step-by-step explanation:

For this case we have the following expression for the average number of words per minutes typed adter t weeks:

N(t) = \frac{95}{1+8.5 e^{-0.12t}}

Part a

For this case we just need to replace the value of t=10 in order to see what we got:

N(t=10) = \frac{95}{1+8.5 e^{-0.12(10)}}= \frac{95}{1+ 8.5 e^{-1.2}} = 26.684

So the number of words per minute typed after 10 weeks are approximately 27.

Part b

For this case we just need to replace the value of t=20 in order to see what we got:

N(t=20) = \frac{95}{1+8.5 e^{-0.12(20)}}= \frac{95}{1+ 8.5 e^{-2.4}} = 53.639

So the number of words per minute typed after 20 weeks are approximately 54.

Part c

For this case we want to solve the following equation:

70 =\frac{95}{1+8.5 e^{-0.12t}}

And we can rewrite this expression like this:

1+ 8.5 e^{-0.12t} = \frac{95}{70}= \frac{19}{14}

8.5 e^{-0.12t} = \frac{19}{14}-1= \frac{5}{14}

Now we can divide both sides by 8.5 and we got:

e^{-0.12t} = \frac{\frac{5}{14}}{8.5}= \frac{5}{119}

Now we can apply natural log on both sides and we got:

ln e^{-0.12t} = ln (\frac{5}{119})

-0.12 t = ln(\frac{5}{119})

And then if we solve for t we got:

t = \frac{ln(\frac{5}{119})}{-0.12} = 26.414 weeks

And we can see this on the plot 1 attached.

Part d

If we find the limit when t tend to infinity for the function we have this:

lim_{t \to \infty} \frac{95}{1+8.5 e^{-0.12t}} = 95

So then the number of words per minute have a limit and is 95 as t increases without bound.

8 0
3 years ago
a first number plus twice a second number is 4. twice the first number plus the second number totals 26. find the numbers
blagie [28]

Answer:

a = 16

b = -6

Step-by-step explanation:

a + 2b = 4

2a + b = 26

2a + 4b = 8

2a + b = 26

3b = -18

b = -6

a + 2(-6) = 4

a - 12 = 4

a = 16

3 0
2 years ago
Subtract 2x – 15x + 6 from 5x + 23x - 4
bagirrra123 [75]

Answer:

2

Step-by-step explanation:

8 0
2 years ago
2x^3-4xy(x+y^2) = 7y<br> y+ 25xy = 0
bagirrra123 [75]

Answer:

Answer

Step-by-step explanation:

2x^3-4xy(x+y^2) = 7y

y+ 25xy = 0

4 0
3 years ago
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