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kirill [66]
3 years ago
14

A population of mice is increasing exponentially. On Monday there were 120 most. One month later there were 132 most. Ready func

tion tomorrow the situation. Determine the percent increase of the population of most of each month.
Mathematics
1 answer:
djyliett [7]3 years ago
5 0

Answer:

y=120 * 1.1^x --- function

The monthly rate is 10%

Step-by-step explanation:

Given

Let

x \to months

y \to mice

So, we have:

(x_1,y_1) = (0,120) --- Monday

(x_2,y_2) = (1,132) --- One month later

Required

The function

The function is represented as:

y=ab^x

In (x_1,y_1) = (0,120), we have:

120 = a * b^0

120 = a * 1

120 = a

a=120

In (x_2,y_2) = (1,132), we have:

132 = a * b^1

132 = a * b

Substitute: a=120

132 = 120 * b

Solve for b

b = \frac{132}{120}

b = 1.1

So, the function is:

y=ab^x

y=120 * 1.1^x

To calculate the monthly rate (r), we have:

y =a(1 + r)^x

Compare to: y =ab^x

1 + r = b

Make r the subject

r = b-1

Substitute b = 1.1

r = 1.1-1

r = 0.1

Express as percentage

r = 0.1*100\%

r = 10\%

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Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

  • MO/Shortest MO/Medium and MO/Longest

a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

The next shortest side is the side opposite ∠M(61°) = \frac{}{NO}

The longest side is the side opposite ∠O(65°) = \frac{}{MN}

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

The mean number of minutes spent on aerobic training is found as follows;

Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

Learn more here:

brainly.com/question/2962546

4 0
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Ed buys a vase for £24 and adds 25% onto the price before putting it into his shop window.
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zlopas [31]

Answer:

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Step-by-step explanation:

the side is same as 57

what times 3 is 57?

57/3 is 19

AB is 19

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