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maks197457 [2]
3 years ago
7

If r is-25 and s is 20 what is the distance between

Mathematics
1 answer:
mariarad [96]3 years ago
6 0

Greetings!

The distance between r & s would be 46.

-25 -24 -23 -22 -21 -20 -19 -18 -17 -16 -15 -14 -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

Hope this helps, have a nice day!

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Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane
liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

Answer:

Rate = 0.935042^\circ /cm

Step-by-step explanation:

Given

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

T(x,y) =x\sin2y

r = 1m

v = 2m/s

Express the given point P as a unit tangent vector:

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

u = \frac{\sqrt 3}{2}i - \frac{1}{2}j

Next, find the gradient of P and T using: \triangle T = \nabla T * u

Where

\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})}  = (sin \sqrt 3)i + (cos \sqrt 3)j

So: the gradient becomes:

\triangle T = \nabla T * u

\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] *  [\frac{\sqrt 3}{2}i - \frac{1}{2}j]

By vector multiplication, we have:

\triangle T = (sin \sqrt 3)*  \frac{\sqrt 3}{2} - (cos \sqrt 3)  \frac{1}{2}

\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)

\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5

\triangle T = 0.935042

Hence, the rate is:

Rate = \triangle T = 0.935042^\circ /cm

3 0
2 years ago
What is the slope of the line i ready
goldfiish [28.3K]

Could you attach an image of the slope? Because i dunno what lesson you're on....

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5 0
3 years ago
HELP PLEASE!!!!!!!!!!!
sashaice [31]
The simplified expression should be 3/7
3 0
3 years ago
josue earned $56.25 fixing a coding issue with a popular website.it took him a total of 4.5 hours to fix the issue.The equation
Marina CMI [18]
In your calculator
Divide 56.25 by 4.5










That should equal 12.50
To double check you can
12.50 x 4.5 = 56.25

5 0
3 years ago
Find the equation of the line between (7,−9) and (5,6) in slope intercept form.
poizon [28]
Set y=ax+b pass (7,-9) (5,6)
=》-9=7a+b
6=5a+b
=》2a=-15
a=-15/2
b=6-5a=6+37.5=43.5
=》y= -15/2(x)+43.5
2y+15x=87
5 0
3 years ago
Read 2 more answers
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