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maks197457 [2]
3 years ago
7

If r is-25 and s is 20 what is the distance between

Mathematics
1 answer:
mariarad [96]3 years ago
6 0

Greetings!

The distance between r & s would be 46.

-25 -24 -23 -22 -21 -20 -19 -18 -17 -16 -15 -14 -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

Hope this helps, have a nice day!

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4/9 is it equivalent to 20/36
Tasya [4]
No because

36 / 9 = 4

20 / 4 = 5

So they are multiplied by different amounts so they aren’t equivalent
5 0
3 years ago
Read 2 more answers
Parte de Cálculo: En cada una de las siguientes proporciones, utilizar regla de tres para determinar el valor desconocido
sineoko [7]

Answer:

<u><em>x = 4</em></u>

<u><em>x = 3</em></u>

<em><u>x = 10</u></em>

<u><em>x = 3</em></u>

<em><u>x = 16</u></em>

<em><u>x = 35</u></em>

Step-by-step explanation:

\frac{x}{5} :\frac{8}{10}

x · 10 = 5 · 8

10x = 40

10x ÷ 10 = 40 ÷ 10

<u><em>x = 4</em></u>

\frac{8}{12} :\frac{2}{x}

x · 8 = 12 · 2

8x = 24

8x ÷ 8 = 24 ÷ 8

<u><em>x = 3</em></u>

\frac{15}{3} :\frac{x}{2}

x · 3 = 15 · 2

3x = 30

3x ÷ 3 = 30 ÷ 3

<em><u>x = 10</u></em>

\frac{x}{6}:\frac{6}{12}

x · 12 = 6 · 6

12x = 36

12x ÷ 12 = 36 ÷ 12

<u><em>x = 3</em></u>

\frac{x}{8} :\frac{4}{2}

x · 2 = 8 · 4

2x = 32

2x ÷ 2 = 32 ÷ 2

<em><u>x = 16</u></em>

\frac{10}{2} :\frac{x}{7}

x · 2 = 10 · 7

2x = 70

2x ÷ 2 = 70 ÷ 2

<em><u>x = 35</u></em>

5 0
3 years ago
What is the value of the 30th percentile for the data set? 6283 5700 6381 6274 5700 5896 5972 6075 5993 5581 5972 6274 6075 5896
Alex17521 [72]
<h2>Answer:</h2>

5896

<h2>Step-by-step explanation:</h2>

Given data set:

6283 5700 6381 6274 5700 5896 5972 6075 5993 5581 5972 6274 6075 5896

To calculate the 30th percentile;

<em>i. Rearrange the given data set in ascending order.</em>

5581 5700 5700 5896 5896 5972 5972 5993 6075 6075 6274 6274 6283 6381

<em>ii. Use the following formula to get the index of the value at the 30th percentile.</em>

N = p(n)

<em>Where;</em>

N = the number of data points at or below the intended percentile.

p = the intended percentile.

n = the number of points in the data.

<em>In this case;</em>

p = 30 percent = 0.3

n = 14

<em>Substitute these values into the equation;</em>

N = 0.3(14)

N = 4.2

<em>iii. From the calculated index, find the value of the 30th percentile.</em>

If the index is a whole number x, the desired percentile is the average of the values at index x and x+1.

For example if the index is 4, then the desired percentile is the average of the values at index 4 and 5. In our case, that will be;

\frac{5896+5896}{2} = 5896

If the index is a decimal number, it is rounded up to the nearest integer. The value at the rounded index is the desired percentile.

For example, in our case, the index is 4.2 which when rounded up becomes 4.

Therefore, the data point or value at index 4 is the 30th percentile. From the arrangement in (ii) above, that will be 5896. i.e

5581 5700 5700 <u>5896</u> 5896 5972 5972 5993 6075 6075 6274 6274 6283 6381

8 0
3 years ago
Can someone please explain the steps to solve these questions.
Amiraneli [1.4K]
Alright! So to solve these questions, you need to find out the difference. You can use ratios to solve this. For example, question #25:

A class had 30 pupils at the beginning of this school term, but now has 5 more pupils. What is the percent of increase?

The question is basically asking how much 5 is in ratio to 30. So just divide 5 (the given amount) by 30 (the total amount). The answer is 0.16, or 16%
3 0
3 years ago
What is this answer?
Angelina_Jolie [31]
A because inverse is the opposite order so instead of -3/1 or 5/1 it becomes 1/-3 and 1/5
3 0
2 years ago
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