Just convert all your measurements. 1gallon is 4 quarts. So 9 gallons= 36qt and 6 gallons= 24qt so the question becomes 36qt+1qt+24qt+1qt=62qt or 15.5 gallons.

7 0

3 years ago

Read 2 more answers

Find the length AB round your answer to the tenth

Kobotan [32]

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$AB = \sqrt{ ({3 - ( - 2)})^{2} + ({4 - 0})^{2} } \\$

$AB = \sqrt{ ({3 + 2})^{2} + {4}^{2} }$

$AB = \sqrt{ {5}^{2} + {4}^{2} }$

$AB = \sqrt{25 + 16}$

$AB = \sqrt{41}$

$AB = 6.403$

$AB = 6.4$

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3 0

2 years ago

Two towers face each other separated by a distance = 15 m. As seen from the top of the first tower, the angle of depression of t

Crazy boy [7]

Answer:

Height of second tower = 17.32m

Step-by-step explanation:

I have attached a diagram depicting the question.

From the diagram, The first tower is depicted by side AEB and the second tower CD.

While d is the distance that separates the two towers and it's given as 15m.

Now, since the angle of depression of the second tower’s base is 60°, then for triangle BAC. Angle C = 60°.

Thus; using trigonometric ratios;

tan 60° = AB/AC.

This gives; AB = d*tan 60°

Similarly, for the triangle BED, BE = d*tan 30°

Since, AE = CD, thus ;

CD = AB − BE

CD = d (tan 60° − tan 30°)

CD = 15(1.7321 − 0.5774)

CD = 15 × 1.1547

CD ≈ 17.32 m.

So, height of second tower = 17.32 m

7 0

2 years ago

¿Cuántos quilómetros recorrerá una locomotora en 5 horas, si marcha a una velocidad de 82 kilómetros

kicyunya [14]

Step-by-step explanation:

Datos;

una locomotora

recorre 5 horas

a una velocidad de 82 km/h

Se asume que la locomotora lleva un movimiento rectilíneo uniforme.

Su recorrido esta descrito por la siguiente ecuación de posición;

x = x₀+ v · t

x-x₀ = d = v · t

siendo;

d = distancia recorrida

v = 82 km/h

t = 5 horas

Sustituir:

d = (82)(5)

d = 410 km

82km/h * 5h= 410km

La locomotora recorrerá 410km

6 0

3 years ago