Answer:
Step-by-step explanation:
Given y = coskt
y' = -ksinkt
y'' = -k²coskt
Substitute this y'' into the expression 25y'' = −16y
25(-k²coskt) = -16(coskt)
25k²coskt = 16(coskt)
25k² = 16
k² = 16/25
k = ±√16/25
k = ±4/5
b) from the DE 25y'' = −16y
Rearrange
25y''+16y = 0
Expressing using auxiliary equation
25m² + 16 = 0
25m² = -16
m² = -16/25
m = ±4/5 I
m = 0+4/5 I
Since the auxiliary root is complex number
The solution to the DE will be expressed as;
y = Asinmt + Bsinmt
Since k = m
y = Asinkt+Bsinkt where A and B are constants
The u.s. department of education reported that for the past seven years 4,033, 5,652, 6,407, 7,201, 8,719, 11,154, and 15,121 pe
Sergeeva-Olga [200]
Hello there,
Let me help you answer this question mathematically.
To calculate average of people per year that gained bachelor degree sum all data given per year and divide with the number of years data was recorded.
Hope this helps answer your question!
r3t40
Answer:
Step-by-step explanation:
x = cos θ + sin(10θ)
y = sin θ + cos(10θ)
Take derivative with respect to θ:
dx/dθ = -sin θ + 10 cos(10θ)
dy/dθ = cos θ - 10 sin(10θ)
Divide:
dy/dx = (dy/dθ) / (dx/dθ)
dy/dx = (cos θ - 10 sin(10θ)) / (-sin θ + 10 cos(10θ))
Evaluate the derivative at θ=0:
dy/dx = (cos 0 - 10 sin 0) / (-sin 0 + 10 cos 0)
dy/dx = 1/10
Evaluate the parametric functions at θ=0:
x = cos 0 + sin 0 = 1
y = sin 0 + cos 0 = 1
Writing the equation of the tangent line in point-slope form:
y - 1 = 1/10 (x - 1)
