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3 years ago

A rectangle has a perimeter of 110 inches. The rectangle' s length is five more than twice the width.

Mathematics

1 answer:

77julia77 [94]3 years ago

4 0

Answer:

Length is 38 $\frac{1}{3}$ inches

Width is 16 $\frac{2}{3}$ inches

Step-by-step explanation:

Let the width be x inches

The length will be 2x + 5 inches

The perimeter is 110 inches

Perimeter is given by (2 × length) + (2 × width)

2(2x + 5) + 2x = 110 inches

4x + 10 + 2x = 110 inches

6x = 100 inches

x (width) = 100/6 = 16 $\frac{2}{3}$ inches

Length = 2(100/6) + 5 = 38 $\frac{1}{3}$ inches.

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The area of polygon MNOPQR = Area of a rectangle that is 9 square units + Area of a rectangle that is ___ square units. (Input w

vekshin1

You have the polygon MNOPQR which can be expressed as two rectangles pasted one next to each other.

To see the two rectangles in the picture, you can draw a line parallel to segment MR througn point N.

From the original picture you can state the dimensions of both rectangles.

Call S, the point where the line that you drew intercepts the segment RQ.

Then one rectangle is MNSR and the other rectangle is OPQS.

The measures of the sides of the rectangle MNSR are:

- the length of MN = length of SR = base

- the length of MR = the length of NS.= height

So its area is base * height, which you can all A1.

The measured of the rectangle OPQS are:

- segment OP = segment SQ = segment QR - segment SR = base

- segment PQ = segment OS = height

So its area is base * height, which you can call A2.

Then the area of the polygon MNOPQRS is A1 + A2. One of them is 9 u^2 and the other is what the answer is asking for, and that you have calculated above.

With this procedure you can tell the value needed.

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3 years ago

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Vlad1618 [11]

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2 years ago

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lilavasa [31]

Answer:

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Step-by-step explanation:

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2 years ago

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The height of a triangle is 4 times its base. if he are of a triangle is 200cm, what is the height

uranmaximum [27]

A = (h * b) / 2
A = 200
h = 4b

200 = (b(4b) / 2
200 * 2 = b * 4b
400 = 4b^2
400 / 4 = b^2
100 = b^2
sqrt 100 = b
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h = 4b
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3 years ago

A boat sails on a bearing of 77 degrees for 135 miles and then turns and sails 207 miles on a bearing of 192 degrees. Find the d

Andrew [12]

Answer:

193.53 miles

Step-by-step explanation:

Please see the diagram for understanding of how the angles were derived,

Applying Alternate Angles, ABO =77 degrees

The bearing from B to C is 192=180+12 degrees

Subtracting 12 from 77, we obtain the angle at B as 65 degrees.

We want to determine the boat's distance from its starting point.

In the diagram, this is the line AC.

Applying Law of Cosines:

$b^2=a^2+c^2-2acCosB\\b^2=207^2+135^2-2(207)(135)Cos65^\circ\\b^2=37453.8654\\b=\sqrt{37453.8654} \\b=193.53\: miles$

The distance of the boat from its starting point is 193.53 miles (correct to 2 decimal places).

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3 years ago