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Kruka [31]
3 years ago
8

cone is inscribed in a cylinder. A square pyramid is inscribed in a rectangular prism. The cone and the pyramid have the same vo

lume. Part of the volume of the cylinder, 1 V 1 , is not taken up by the cone. Part of the volume of the rectangular prism, 2 V 2 , is not taken up by the square pyramid. What is the relationship of these two volumes, 1 V 1 and 2 V 2 ?
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

The answer is "v_1 \ and\ v_2 are equal".

Step-by-step explanation:

Its volume could be defined both by cone as well as the cylinders

\to \text{(base area)} \times \text{(solid height)} \times (\frac{1}{3})\\\\

We are planning to write this as V = \frac{Bh}{3}

When we relate this formula to the cylindrical and prism volume formula, we can see that when we multiply the cone volume by 3, the cylinder size where it is registered comes in. The very same goes for the pyramid as well as the inscription of the rectangular prism. That both pyramid and the cone have the same volume V, hence it would have the same volume of a cell and rectangle prism. v_1 \ and\ v_2 are so similar.

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Tim has £750.<br> Liz has £659.<br><br> Work out much more money Tim has.
lbvjy [14]

Answer:

Tim has £91 more than Liz.

Step-by-step explanation:

£750-£659=£91

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1 year ago
A cheetah ran 196 meters in 8 seconds. Select the TWO correct statements that are true if the cheetah runs at a constant rate.
Nata [24]

Answer

. The cheetah ran 24.5 meters per second.

Step-by-step explanation:

Its that one because if you divide the meters by seconds which is 196/8 you would get 24.5 meters per second

6 0
3 years ago
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What is the value of x in the equation −3(10x − 12) + 15x = 54?
Deffense [45]
It’s B. Yeah trust me in this one
4 0
2 years ago
AB and CD are straight line segments.
goldfiish [28.3K]

Answer:

<h3>i) Angle AOC is 95° </h3><h3>Reason:- Angle AOC is equal to Angle DOB since they are Vertically Opposite Angles. </h3>

<h3> ii) Angle BOC is 85° </h3><h3>Reason:- Angle AOC + Angle BOC - 180° (they lie in a straight line so they are a linear pair. Sum of the angles will be 180°) </h3><h3> Angle AOC is 95°, So:- </h3><h3> 95° + Angle BOC = 180° </h3><h3> Angle BOC= 180° - 95° </h3><h3> Angle BOC = 85° </h3><h3> </h3><h3>iii) Angle DOE is 17° </h3><h3>Reason:- Angle AOE+ Angle DOE+ Angle DOB = 180° (they lie in a straight line so they're a linear pair. Sum of the angles will be 180°) </h3><h3> So, </h3><h3> 68° + Angle DOE+ 95° = 180° </h3><h3> 163° + Angle DOE = 180° </h3><h3> Angle DOE= 180° - 163° </h3><h3> Angle DOE is 17°</h3>
5 0
3 years ago
A particle is moving with acceleration a ( t ) = 18 t + 16 . Its position at time t = 0 is s ( 0 ) = 10 and its velocity at time
MatroZZZ [7]

Answer:

s(8)=2186

Step-by-step explanation:

A particle is moving with acceleration modeled by the function:

a(t)=18t+16

We are given that its position s(t) at <em>t</em> = 0 is 10 and that its velocity v(t) at <em>t</em> = 0 is 16.

And we want to find its position at <em>t</em> = 8.

Velocity is the integral of the acceleration. Hence:

\displaystyle v(t)=\int a(t)\, dt=\int 18t+16\, dt

Find the velocity. Remember the constant of integration!

v(t)=9t^2+16t+C

Since v(t) is 16 when <em>t</em> = 0:

(16)=9(0)^2+16(0)+C\Rightarrow C=16

Hence, our velocity is given by:

v(t)=9t^2+16t+16

Position is the integral of the velocity. Hence:

\displaystyle s(t)=\int v(t)\, dt=\int 9t^2+16t+16\, dt

Integrate:

\displaystyle s(t)=3t^3+8t^2+16t+C

s(t) is 10 when <em>t</em> = 10. Hence:

C=10

So, our position function is:

s(t)=3t^3+8t^2+16t+10

The position at <em>t</em> = 8 will be:

s(8)=3(8)^3+8(8)^2+16(8)+10=2186

3 0
2 years ago
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