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Zanzabum
3 years ago
13

The pH of a strong base is 12.2 at 25 degrees. what is its hydroxide-ion concentration?

Chemistry
1 answer:
marta [7]3 years ago
3 0

Answer:

[OH⁻] = 0.016

Explanation:

Given data:

pH = 12.2

Hydroxide ion concentration = ?

Solution:

It is known that,

pH + pOH = 14

12.2 + pOH = 14

pOH = 14 - 12.2

pOH = 1.8

pOH = -log [OH⁻]

1.8 = -log [OH⁻]

10⁻¹°⁸ = [OH⁻]

[OH⁻] = 0.016

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The accepted value for the mass of a moonrock is 46.37 g. In an experiment the rock is measured to be 47.25 g. What is the perce
Artist 52 [7]

Answer:

The answer is

<h2>2.00 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual measurement = 46.37 g

error = 47.25 - 46.37 = 0.88

The percentage error of the measurement is

P(\%) =  \frac{0.88}{46.37}  \times 100 \\  = 1.89777873...

We have the final answer as

<h3>2.00 %</h3>

Hope this helps you

4 0
3 years ago
How many CO2 molecules in 0.0189 mol of CO2?
Blizzard [7]

Answer:

option C is correct = 1.14 × 10²² molecules of  CO₂

Explanation:

Given data:

Number of moles of CO₂ = 0.0189 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

For given question:

1 mole of CO₂ =  6.022 × 10²³ molecules of  CO₂

0.0189 mol of CO₂ ×  6.022 × 10²³ molecules of  CO₂ / 1mol

1.14 × 10²² molecules of  CO₂

Thus, option C is correct.

4 0
3 years ago
Massive amounts of energy are contained in an atom's: Select one:
melamori03 [73]
Nucleus.
____________
6 0
4 years ago
True or False: All material has the same density.
Burka [1]

Answer:

Different materials have different densities. So it is False

4 0
3 years ago
Read 2 more answers
If the volume of a gas container at 32 degrees Celsius changes from 1.55 L to 755 mL, what will the final temperature be?
QveST [7]
So to solve this you need to know Charles’s law which is: V1/T1=V2/T2. Where T1 and V1 is the initial volume and Temperature and V2 and T2 is the temperature and volume afterwards. So first plug in the numbers you are given. V1= 1.55L T1= 32C° V2= 755mL T2=?. Since your volumes are two different units you change 755mL to be in L so that would be 0.755 L. And since your temp isn’t in Kelvin you do 273+32= 305K°. You then would rearrange your equation to solve for T2 which is V2T1/V1. Then you plug in your numbers (0.755L)(305K)/1.55L. Then you solve and would be 148.5645161 —> 1.49 x 10^2 K
4 0
3 years ago
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