1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Phoenix [80]
2 years ago
5

What are compounds?

Chemistry
2 answers:
djverab [1.8K]2 years ago
5 0

Answer:

2)Homogenous Mixture

Kryger [21]2 years ago
4 0

Answer:

pure substance - substances made up of one type of atom or molecule

homogeneous- solid, liquid, gas , has the same proportions

heterogeneous- it has basically anything

Explanation:

You might be interested in
CH4 with pressure 1 atm and volume 10 liter at 27°C is passed into a reactor with 20% excess oxygen, how many moles of oxygen is
BaLLatris [955]

Answer : The moles of O_2 left in the products are 0.16 moles.

Explanation :

First we have to calculate the moles of CH_4.

Using ideal gas equation:

PV=nRT

where,

P = pressure of gas = 1 atm

V = volume of gas = 10 L

T = temperature of gas = 27^oC=273+27=300K

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

(1atm)\times (10L)=n\times (0.0821L.atm/mol.K)\times (300K)

n=0.406mole

Now we have to calculate the moles of O_2.

The balanced chemical reaction will be:

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that,

As, 1 mole of CH_4 react with 2 moles of O_2

So, 0.406 mole of CH_4 react with 2\times 0.406=0.812 moles of O_2

Now we have to calculate the excess moles of O_2.

O_2 is 20 % excess. That means,

Excess moles of O_2 = \frac{(100 + 20)}{100} × Required moles of O_2

Excess moles of O_2 = 1.2 × Required moles of O_2

Excess moles of O_2 = 1.2 × 0.812 = 0.97 mole

Now we have to calculate the moles of O_2 left in the products.

Moles of O_2 left in the products = Excess moles of O_2 - Required moles of O_2

Moles of O_2 left in the products = 0.97 - 0.812 = 0.16 mole

Therefore, the moles of O_2 left in the products are 0.16 moles.

7 0
3 years ago
A soft drink contains 12.1% sucrose (C12H22O11) by mass. What volume of the soft drink solution in milliliters contains 102.5 g
galina1969 [7]

The volume of the soft drink solution in milliliters that contains 102.5 g of sucrose is 11.93mL.

<h3>How to calculate volume?</h3>

The volume of a solution can be calculated by dividing the mass by the density. That is;

Volume = mass/density

According to this question, a soft drink contains 12.1% sucrose (C12H22O11) by mass. This means that the mass of the sucrose is

12.1/100 × 102.5 = 12.40g of sucrose

Volume = 12.40g ÷ 1.04g/mL

Volume = 11.93mL

Therefore, the volume of the soft drink solution in milliliters that contains 102.5 g of sucrose is 11.93mL.

Learn more about volume at: brainly.com/question/1578538

4 0
2 years ago
Cole is working with radioactive particles and has set up a shield made of aluminum for protection. Which of the following will
koban [17]

Answer:

C.) Alpha, beta, and gamma particles

Explanation:

A dense shield of aluminium can protect Cole from all the listed types of radiation produced from the radioactive particles.

A radioactive protector has very unique and specie ability to contain and prevent the movement of radiations of any types from going into the body.

The strongest and most penetrating radiations are the gamma rays. Any material that can prevent the movement of these rays can halt alpha and beta particles too.

An aluminium shield is made up of multiple layers of aluminium stacked together and it provides enough resistance.

6 0
3 years ago
Read 2 more answers
What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Br2(l) and I-(aq) Use the reduction po
Vikki [24]

Answer:

1.58×10E18

Explanation:

Since we have the reduction potentials we could make decisions regarding which one will be the anode or cathode. Evidently, bromine having the more positive reduction potential will be the cathode while the iodine will be the anode.

E°cell= 1.07- 0.53= 0.54 V

E°cell= 0.0592/n logK

0.54 = 0.0592/2 logK

logK= 0.54/0.0296

logK= 18.2

K= Antilog (18.2)

K= 1.58×10^18

3 0
3 years ago
Which of these molecules has an overall dipole moment? O A. F2 B. H2S C. CH4 D. CO2​
adelina 88 [10]

Answer:

i think the answer is B cus i think of that

4 0
2 years ago
Other questions:
  • Two major discoveries of the gold foil experiment
    13·1 answer
  • Which of these equations is balanced? a. 3 H2SO4 + 2Al → Al2(SO4)3 + 3H2 b. 2KCl + Pb(NO3)2 → KNO3 + PbCl2 a b a and b neither
    15·2 answers
  • What is the formula for chromium (III) nitrate?
    13·2 answers
  • what is the substances would be produced during the chemical reaction between potassium hydroxide and hydrochloric acid
    11·2 answers
  • Which particle changes to create an isotope of an atom? <br> A.proton<br> B.neutron<br> C.electron
    5·1 answer
  • A chemical property of oxygen is that it ____
    6·2 answers
  • Please helppp !<br> convert 0.648 L of SO2 to grams. use correct number of sig figs
    14·1 answer
  • Which type of wind is responsible for moving state to state
    10·1 answer
  • 1) Calculate the empirical formula of a compound with 36g of carbon and 96g of oxygen.
    8·1 answer
  • Need help FAST! Will rate 5
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!