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Mrrafil [7]
2 years ago
6

Helium-neon laser light (λ = 6. 33 × 10^−7 m) is sent through a 0. 63 mm-wide single slit. what is the width of the central maxi

mum on a screen 1. 0 m from the slit?
Chemistry
1 answer:
maw [93]2 years ago
8 0

Helium-neon laser light (λ = 6. 33 × 10⁻⁷ m) is sent through a 0.63 mm wide single slit. The width of the central maximum on a screen 1 m from the slit is 1 mm.

Central maximum on a screen of YDSE shows the point of maximum brightness where constructive interference takes place.

It is dependent on the wavelength of light, distance between the slit and screen and distance between the two slits.

It is given by:

Width of Central Maximum = λD/d

where, λ is the wavelength of light used

D is the distance between the slit and screen

d is the distance between the two slits

Given, λ = 6.33 × 10⁻⁷m

d = 0.63mm = 0.63 × 10⁻³ m

D = 1m

On substituting the value is the above-mentioned formula:

Width of Central Maximum = λD/d

Width of Central Maximum = 6.33 × 10⁻⁷ × 1 / 0.63 × 10⁻³

Width of Central Maximum = 10⁻³ m

Width of Central Maximum = 1 mm

Hence, the Width of Central Maximum is 1 mm.

Learn more about YDSE here, brainly.com/question/17167388

#SPJ4

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Find your answer in the explanation below.

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According to the VSEPR model, the arrangement of electron pairs around NH3 and CH4 is A. the same, because in each case there ar
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Answer:

Option "B" is correct.

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If two balls have the same volume, but ball A has twice as much mass as ball B, which one will have the greater density? ball A,
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Density (D) is defined as the amount or mass (m) of a substance present in a unit volume(V). It can be expressed mathematically as:

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i.e. D = m/V -------(1)

Units: g/cm3

a)

If m1, V1 and D1 = mass, volume  and density respectively of ball A

m2, V2 and D2 = mass, volume and density respectively of ball B

It is given that: V1 = V2; but m1 = 2m2

Based on equation (1) we have:

D1/D2 = (m1/V1)* (V2/m2) = (2m2/V2)*(V2/m2) = 2

Thus, density of ball A is twice that of B.

Ans: Ball A will have a greater density than B

b)

If m1, V1 and D1 = mass, volume  and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

It is given that:

V1 = 3V2 and m2 = 1/3(m1) i.e m1 = 3m2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (3m2/3V2)*(V2/m2) = 1

Thus, D1 = D2

Ans: Their densities are equal

c)

If m1, V1 and D1 = mass, volume  and density respectively of ball P

m2, V2 and D2 = mass, volume and density respectively of ball Q

It is given that:

m1 = m2 but V1 = 2V2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (m2/2V2)*(V2/m2) = 1/2

Thus, D1 = 1/2(D2)

Ans: Ball Q will have a greater density.

d)

If m1, V1 and D1 = mass, volume  and density respectively of ball X

m2, V2 and D2 = mass, volume and density respectively of ball Y

It is given that:

V1 = 2V2 and m1 = 1/2(m2)

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = ((1/2(m2)/2V2)*(V2/m2) = 1/4

Thus, D1 = 1/4(D2)

Ans: Ball Y will have a greater density.



5 0
3 years ago
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