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Mrrafil [7]
2 years ago
6

Helium-neon laser light (λ = 6. 33 × 10^−7 m) is sent through a 0. 63 mm-wide single slit. what is the width of the central maxi

mum on a screen 1. 0 m from the slit?
Chemistry
1 answer:
maw [93]2 years ago
8 0

Helium-neon laser light (λ = 6. 33 × 10⁻⁷ m) is sent through a 0.63 mm wide single slit. The width of the central maximum on a screen 1 m from the slit is 1 mm.

Central maximum on a screen of YDSE shows the point of maximum brightness where constructive interference takes place.

It is dependent on the wavelength of light, distance between the slit and screen and distance between the two slits.

It is given by:

Width of Central Maximum = λD/d

where, λ is the wavelength of light used

D is the distance between the slit and screen

d is the distance between the two slits

Given, λ = 6.33 × 10⁻⁷m

d = 0.63mm = 0.63 × 10⁻³ m

D = 1m

On substituting the value is the above-mentioned formula:

Width of Central Maximum = λD/d

Width of Central Maximum = 6.33 × 10⁻⁷ × 1 / 0.63 × 10⁻³

Width of Central Maximum = 10⁻³ m

Width of Central Maximum = 1 mm

Hence, the Width of Central Maximum is 1 mm.

Learn more about YDSE here, brainly.com/question/17167388

#SPJ4

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alexdok [17]

Answer:

518 mL

Explanation:

We can solve this using Boyle's Law Formula

P1V1 = P2V2

where p1 = initial pressure, p2 = final pressure, v1 = initial volume and v2 = final volume

here , the initial pressure is 1 atm and the initial volume is 725mL

we are given the final pressure 1.4 and we need to find the final volume

so we have p1v1 = p2v2

==> plug in p1 = 1 , v1 = 725 mL and p2 = 1.4

(1)(725) = (1.4)v2

==> multiply 1 and 725

725 = (1.4)(v2)

==> divide both sides by 1.4

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