Question

Helium-neon laser light (λ = 6. 33 × 10^−7 m) is sent through a 0. 63 mm-wide single slit. what is the width of the central maximum on a screen 1. 0 m from the slit?

Answer 1

Helium-neon laser light (λ = 6. 33 × 10⁻⁷ m) is sent through a 0.63 mm wide single slit. The width of the central maximum on a screen 1 m from the slit is 1 mm.

Central maximum on a screen of YDSE shows the point of maximum brightness where constructive interference takes place.

It is dependent on the wavelength of light, distance between the slit and screen and distance between the two slits.

It is given by:

Width of Central Maximum = λD/d

where, λ is the wavelength of light used

D is the distance between the slit and screen

d is the distance between the two slits

Given, λ = 6.33 × 10⁻⁷m

d = 0.63mm = 0.63 × 10⁻³ m

D = 1m

On substituting the value is the above-mentioned formula:

Width of Central Maximum = λD/d

Width of Central Maximum = 6.33 × 10⁻⁷ × 1 / 0.63 × 10⁻³

Width of Central Maximum = 10⁻³ m

Width of Central Maximum = 1 mm

Hence, the Width of Central Maximum is 1 mm.

Learn more about YDSE here, brainly.com/question/17167388

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