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Mrrafil [7]
1 year ago
6

Helium-neon laser light (λ = 6. 33 × 10^−7 m) is sent through a 0. 63 mm-wide single slit. what is the width of the central maxi

mum on a screen 1. 0 m from the slit?
Chemistry
1 answer:
maw [93]1 year ago
8 0

Helium-neon laser light (λ = 6. 33 × 10⁻⁷ m) is sent through a 0.63 mm wide single slit. The width of the central maximum on a screen 1 m from the slit is 1 mm.

Central maximum on a screen of YDSE shows the point of maximum brightness where constructive interference takes place.

It is dependent on the wavelength of light, distance between the slit and screen and distance between the two slits.

It is given by:

Width of Central Maximum = λD/d

where, λ is the wavelength of light used

D is the distance between the slit and screen

d is the distance between the two slits

Given, λ = 6.33 × 10⁻⁷m

d = 0.63mm = 0.63 × 10⁻³ m

D = 1m

On substituting the value is the above-mentioned formula:

Width of Central Maximum = λD/d

Width of Central Maximum = 6.33 × 10⁻⁷ × 1 / 0.63 × 10⁻³

Width of Central Maximum = 10⁻³ m

Width of Central Maximum = 1 mm

Hence, the Width of Central Maximum is 1 mm.

Learn more about YDSE here, brainly.com/question/17167388

#SPJ4

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If it requires 75.0mL of 0.500M NaOH to neutralize 165.0 mL of an hcl solution what is the concentration of the hcl solution
Kaylis [27]

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0.027 M HCl

Explanation:

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7 0
3 years ago
a sample of solid is decomposed and found to contain 6.52g of potassium, 4.34 g of chromium and 5.34 of oxygen, what is the empi
Fynjy0 [20]

Answer:

K₂CrO₅

Explanation:

The empirical formula is the simplest formula of a compound. To find the empirical formula, we follow the procedure below:

Elements                         Potassium                 Chromium         Oxygen

Mass                                  6.52                             4.34                  5.34

Molar mass                          39                               60                      16

Number of moles             6.52/39                     4.34/60             5.34/16

                                             0.167                          0.072              0.333

Divide through by

the smallest                      0.167/0.072             0.072/0.072          0.333/0.072

                                            2.3                               1                                4.6

                                             2                                 1                                  5

Empirical formula K₂CrO₅

5 0
3 years ago
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