Approximate irrational number 34 to the nearest 0.05
1 answer:
First of all, 34 is a rational number: 
If you mean the square root of 34 (and I think you do), then here is one way to approximate it:
We know that the √25 is 5 and the √6 = 36 and that the √34 is somewhere between those two numbers. It is certainly closer to 36 than 25 so I am going to guess high. I will guess 5.8 I will do 34 ÷ 5.8 = (about) 5.8620. That was close but not rounded to the nearest .05 since it could be 5.80 (my guess) or 5.90 (5.86 rounded to the nearest 05.
Let's do it one more time: I will find the average of the the number I divided by and the quotient: (5.8 + 5.6820) ÷ 2 = 5.831 I will use this as my new divisor with 34
34 ÷ 5.831 = (about 5.8309)
You can see that I now know the √34 out to the nearest hundred. It is about 5.83
Notice that as many times as I could keep doing this procedure, I will never get a number that, when multiplied by itself, gives me exactly 34. That is the definition of an irrational number.
If you mean the square root of 34 (and I think you do), then here is one way to approximate it:
We know that the √25 is 5 and the √6 = 36 and that the √34 is somewhere between those two numbers. It is certainly closer to 36 than 25 so I am going to guess high. I will guess 5.8 I will do 34 ÷ 5.8 = (about) 5.8620. That was close but not rounded to the nearest .05 since it could be 5.80 (my guess) or 5.90 (5.86 rounded to the nearest 05.
Let's do it one more time: I will find the average of the the number I divided by and the quotient: (5.8 + 5.6820) ÷ 2 = 5.831 I will use this as my new divisor with 34
34 ÷ 5.831 = (about 5.8309)
You can see that I now know the √34 out to the nearest hundred. It is about 5.83
Notice that as many times as I could keep doing this procedure, I will never get a number that, when multiplied by itself, gives me exactly 34. That is the definition of an irrational number.
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Answer:
If we compare the p value and the significance level assumed we see that
so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance
Step-by-step explanation:
Data given and notation
We can calculate the sample mean and deviation with these formulas:
represent the mean for the sample mean for 1
represent the mean for the sample mean for 2
represent the sample standard deviation for the sample 1
represent the sample standard deviation for the sample 2
sample size selected 1
sample size selected 2
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the average time taken when training under method 1 is less than the average time for Method 2, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".
Calculate the statistic
We can replace in formula (1) the info given like this:
P-value
The first step is calculate the degrees of freedom, on this case:
Since is a one sided test the p value would be:
Conclusion
If we compare the p value and the significance level assumed we see that
so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance