I'll focus on problem 19 and problem 22
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Problem 19
Answers:
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Explanation:
The horizontal lines are parallel. Note the arrow markers along the interior portion of the lines. These similar markers tell us how the lines pair up to be parallel to one another.
Since the horizontal lines are parallel, this means the angles in question are congruent. They are corresponding angles.
x+15 = 102
x = 102-15
x = 87
Which leads to
x+15 = 87+15 = 102
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Problem 22
Answer: y = 27
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Explanation:
We have a pair of alternate exterior angles. They are congruent due to the parallel lines.
Let's solve for y.
7y-55 = 3y+53
7y - 3y = 53+55
4y = 108
y = 108/4
y = 27
Answer:
99.7% of customers have to wait between 8 minutes to 30 minutes for their food.
Step-by-step explanation:
We are given the following in the question:
Mean, μ = 18 minutes
Standard Deviation, σ = 4 minutes
We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.
Empirical Formula:
- Almost all the data lies within three standard deviation from the mean for a normally distributed data.
- About 68% of data lies within one standard deviation from the mean.
- About 95% of data lies within two standard deviations of the mean.
- About 99.7% of data lies within three standard deviation of the mean.
Thus, 99.7% of the customers have to wait:
Thus, 99.7% of customers have to wait between 8 minutes to 30 minutes for their food.
I suppose I can do that and end up spending 6.50$?
1.25 x 5.20 = 6.50 final amount due.
Answer:
Option C
The length of RT is 14
Step-by-step explanation:
For a given Right Triangle
m∠R = 90°, RG = 17, TG = 22
Now, <u>By Pythagoras Theorem</u>
(RT)² + (RG)² = (TG)²
(RT)² = (TG)² - (RG)²
(RT)² = (22)² - (17)²
(RT)² = 484 - 289
(RT)² = 195
RT = √195
RT = √195 = 13.96 = 14
Thus, The length of RT is 14
<u>-TheUnknownScientist</u>
Answer:
531.167 ft²
Step-by-step explanation:
Given data
Dimension of pool
Diameter =24ft
Radius =12ft
If the cover must hang by 1ft around, then the diameter is 26ft
Radius =13ft
Area of cover = πr²
Substitute
Area = 3.142*13²
Area =3.143*169
Area =531.167 ft²
Hence the minimum area is 531.167 ft²
