The density told you the mass covered by one unit of volume of that substance.
Density defines how perfectly the molecules of a substance are packed in a unit of volume.
In the given problem the substances are expressed in g/ml which means that a unit of volume will be 1 mL.
Given ,
Density of mercury = 13.546 g/ml
It means 1mL of mercury will have a mass of 13.546 g, Similarly 1 mL of ethanol will have a mass of 0.789 g.
0.350 L * 10^3 ml/1 L* 13.546/1 mL = 4,741.1 g
The volume of ethanol will have an equal mass is
4741.1 g* 1 mL/0.789g = 6,008.9 mL
6,008.9 mL* 1L/10^3mL = 6.0081 L
Hence the answer is 6.0081 L
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Answer:
electrophilic addition
Explanation:
CH3 - CH = CH2 + Cl-Cl ---> CH3 -CH(Cl) - CH2(Cl)
Copper is a soft, ductile, and malleable metal that bends and stretches easily without breaking. Copper is a versatile metal for construction and manufacturing because of this.
Answer: 
of NaOH
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
Putting in the values:
![10.020=-\log[H^+]](https://tex.z-dn.net/?f=10.020%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=9.55\times 10^{-11}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D9.55%5Ctimes%2010%5E%7B-11%7D)
![[H^+][OH^-]=10^{-14}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%5BOH%5E-%5D%3D10%5E%7B-14%7D)
![[OH^-]=\frac{10^{-14}}{9.55\times 10^{-11}}=1.05\times 10^{-4}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%5Cfrac%7B10%5E%7B-14%7D%7D%7B9.55%5Ctimes%2010%5E%7B-11%7D%7D%3D1.05%5Ctimes%2010%5E%7B-4%7DM)
moles = 
Mass of 
Thus of NaOH is needed to prepare 463 mL of solution with a pH of 10.020
All energy can generally be considered to be either kinetic energy or potential energy<span>. </span>Some specific forms of energy<span>, </span>such as electrical<span>, </span>magnetic, and gravitational energy<span>, </span>can operate in the space around objects and affect other objects that come near<span>. So, the correct answer is B, I believe. :)
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