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Kay [80]
3 years ago
6

3 Write the alpha decay WITH gamma emission for the following element: 92 AL 27

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
4 0

Answer:

Explanation:

In alpha decay alpha ray comes out . Apha ray is nothing but nucleus of helium atom whose atomic no  is 2 and atomic weight is 4 . Hence in alpha decay , atomic weight reduces by 4 and atomic no reduces by 2. For gamma emission , there is no change in atomic number and atomic mass.

⁹²₂₇AL ⇒ ⁸⁸₂₅X + ⁴₂He + γ

X is Manganese .

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During a laboratory experiment, 36.12 grams of Aboz was formed when O2 reacted with aluminum metal at 280.0 K and 1.4 atm. What
kvv77 [185]

Answer:

8.70 liters

Explanation:

  • 3O₂+ 4Al → 2AI₂O₃

First we <u>convert 36.12 g of AI₂O₃ into moles</u>, using its <em>molar mass</em>:

  • 36.12 g ÷ 101.96 g/mol = 0.354 mol AI₂O₃

Then we <u>convert AI₂O₃ moles into O₂ moles</u>, using the stoichiometric coefficients of the reaction:

  • 0.354 mol AI₂O₃ * \frac{3molO_2}{2molAl_2O_3} = 0.531 mol O₂

We can now use the <em>PV=nRT equation</em> to <u>calculate the volume</u>, V:

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5 0
3 years ago
Explain what would happen in Step 2 if the cylinder were heated with the plunger held steady.
Svetradugi [14.3K]

Answer:

be more descriptive

Explanation:

4 0
3 years ago
PLEASE HELP!!!!
shtirl [24]
1) d

2) b because the independent variable is the thing you change/control in an experiment

3) c because the dependent variable is the thing being measured in an experiment

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5) c

6) a

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6 0
4 years ago
To what volume would you need to dilute 200 mL of a 5.85M solution of Ca(OH)2 to make it a 1.95M solution?
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Answer: 600 mL

Explanation:

Given that;

M₁ = 5.85 m

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Now from the dilution law;

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so we substitute

5.85 × 200 = 1.95 × V₂

1170 = 1.95V₂

V₂ = 1170 / 1.95

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8 0
3 years ago
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KATRIN_1 [288]
Beaker does thermometer measures the thermal energy in the air
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