Atomic mass of Sulfur = 32g
32g of Sulfur is one mole.
1g of Sulfur is
96.21g of Sulfur is
Answer:
7.04 g
Explanation:
Let's consider the reaction in the last step of the Ostwald process.
3 NO₂(g) + H₂O(l) → 2 HNO₃(aq) + NO(g)
The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 6.40 g are:
6.40 g × (1 mol/63.01 g) = 0.102 mol
The molar ratio of NO₂ to HNO₃ is 3:2. The reacting moles of NO₂ are:
0.102 mol HNO₃ × (3 mol NO₂/2 mol HNO₃) = 0.153 mol NO₂
The molar mass of NO₂ is 46.01 g/mol. The mass corresponding to 0.153 moles is:
0.153 mol × (46.01 g/mol) = 7.04 g
All pieces will be 17 g/cm^3 because the density is not affected by cutting (assuming the rock is uniform).
Answer:
A. Ba(NO₃)₂(aq) + Na₂CO₃(aq)
Explanation:
- The reaction between aqueous Ba(NO₃)₂ and Na₂CO₃ is a precipitation reaction.
- The complete equation for the reaction is;
Ba(NO₃)₂(aq) + Na₂CO₃(aq) → BaCO₃(s) + NaNO₃(aq)
- Barium carbonate is the precipitate formed during the reaction.
- All nitrates are soluble in water and all salts of sodium are soluble in water, therefore, Ba(NO₃)₂, Na₂CO3, and NaNO₃ are soluble in water.
- Precipitation reaction involves reaction of soluble salts to form a precipitate as one of the product.
Answer:
It's B
Explanation:
The explanation is basically the answer choice lol. Stay safe!