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Svetlanka [38]
3 years ago
14

You have been working to develop a new fictitious compound in the lab. Determine the amount in units of moles​ [mol] of 20 grams

​ [g] of this compound. The compound has the​ formula: upper x 2 upper y 2 upper z 7​, where the components are​ x, amu equals 47​; ​y, amuequals42​; ​z, amu equals 16.
Chemistry
1 answer:
vodomira [7]3 years ago
8 0

From the chemical formula the total mass of the compound can be determined. The mass of the 1 mole of the compound is its molar mass. The atom by which the molecule is generated, the mass of these atoms are expressed in terms of amu or atomic unit mass, but after formation of a molecule in a particular ratio the mass of each of the atom becomes the total molecular weight of the generated molecule. In this case the molecule posses three atoms X, Y and Z which are in a ratio of 2:2:7. Thus the chemical formula of the compound can be written as X_{2}Y_{2}Z_{7}.

So the total mass of the compound in amu is {(2×47)+(2×42)+(7×16)} = {94+84+112}=290 amu.

Thus 1 mole of the compound contains 290 amu or 290 g  by mass.

Henceforth 20 gram of the compound is equivalent to  (20/290) = 0.068 mole.

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96.21g of Sulfur is \frac{96.21}{32} moles=> 3moles(appx)

5 0
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aleksandr82 [10.1K]

Answer:

7.04 g

Explanation:

Let's consider the reaction in the last step of the Ostwald process.

3 NO₂(g) + H₂O(l) → 2 HNO₃(aq) + NO(g)

The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 6.40 g are:

6.40 g × (1 mol/63.01 g) = 0.102 mol

The molar ratio of NO₂ to HNO₃ is 3:2. The reacting moles of NO₂ are:

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5 0
3 years ago
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