You have been working to develop a new fictitious compound in the lab. Determine the amount in units of moles [mol] of 20 grams
1 answer:
From the chemical formula the total mass of the compound can be determined. The mass of the 1 mole of the compound is its molar mass. The atom by which the molecule is generated, the mass of these atoms are expressed in terms of amu or atomic unit mass, but after formation of a molecule in a particular ratio the mass of each of the atom becomes the total molecular weight of the generated molecule. In this case the molecule posses three atoms X, Y and Z which are in a ratio of 2:2:7. Thus the chemical formula of the compound can be written as .
So the total mass of the compound in amu is {(2×47)+(2×42)+(7×16)} = {94+84+112}=290 amu.
Thus 1 mole of the compound contains 290 amu or 290 g by mass.
Henceforth 20 gram of the compound is equivalent to (20/290) = 0.068 mole.
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Answer:
The element will be
Explanation:
Given that,
Number of proton = 80
Number of neutron = 81
Number of electron = 79
We know that,
The atomic number is equal to the number of proton.
So, the atomic number is 80.
According to atomic number,
The element will be mercury.
We need to calculate the atomic mass
Using formula of atomic mass
Put the value into the formula
We need to find the element
Using atomic mass and atomic number
So, the element will be
Put the value of A and Z
Hence, The element will be
Answer:
a) The volume is 5.236x10⁻¹³L
b) The molarity of a single virus is 1.91x10¹² mol/L
c) The molarity for a 100 virus particles is 1.91x10¹⁴ mol/L
Explanation:
a) Given:
D = diameter of the cell = 10 μm
r = radius = 10/2 = 5 μm
The volume of the spherical cell is equal:
If 1 μm³ = 1x10⁻¹⁵L, then 523.6 μm³ = 5.236x10⁻¹³L
b) The molarity is:
For a single virus within the cell
c) For a 100 virus particles the molarity is: