Answer:
a. 5.9 × 10⁻³ M/s
b. 0.012 M/s
Explanation:
Let's consider the following reaction.
2 N₂O(g) → 2 N₂(g) + O₂(g)
a.
Time (t): 12.0 s
Δn(O₂): 1.7 × 10⁻² mol
Volume (V): 0.240 L
We can find the average rate of the reaction over this time interval using the following expression.
r = Δn(O₂) / V × t
r = 1.7 × 10⁻² mol / 0.240 L × 12.0 s
r = 5.9 × 10⁻³ M/s
b. The molar ratio of N₂O to O₂ is 2:1. The rate of change of N₂O is:
5.9 × 10⁻³ mol O₂/L.s × (2 mol N₂O/1 mol O₂) = 0.012 M/s
Answer:
The element will be 
Explanation:
Given that,
Number of proton = 80
Number of neutron = 81
Number of electron = 79
We know that,
The atomic number is equal to the number of proton.
So, the atomic number is 80.
According to atomic number,
The element will be mercury.
We need to calculate the atomic mass
Using formula of atomic mass

Put the value into the formula


We need to find the element
Using atomic mass and atomic number


So, the element will be

Put the value of A and Z
Hence, The element will be 
solution:
Physical properties describe how a material looks. such as color, state of matter, shininess, Other physical properties include density, mp, bp, brittleness, malleability, conductivity, ductility, solubility in water. A physical property can be determined without changing the identity of the material.
Chemical properties describe how a material behaves.such as does it burn, does it corrode, does it react with air, does it react with water, does it act like a metal by giving away electrons o like a nonmetal by taking electrons, what type of bonds will it form, or is it inert, is it acidic or basic, Chemical properties can only be determined during a chemical reaction.
Answer:
a) The volume is 5.236x10⁻¹³L
b) The molarity of a single virus is 1.91x10¹² mol/L
c) The molarity for a 100 virus particles is 1.91x10¹⁴ mol/L
Explanation:
a) Given:
D = diameter of the cell = 10 μm
r = radius = 10/2 = 5 μm
The volume of the spherical cell is equal:

If 1 μm³ = 1x10⁻¹⁵L, then 523.6 μm³ = 5.236x10⁻¹³L
b) The molarity is:

For a single virus within the cell

c) For a 100 virus particles the molarity is:

Answer:
2.5x10^–3 mole.
Explanation:
Data obtained from the question include:
Volume of solution = 25mL
Molarity of HNO3 = 0.1M
Mole of HNO3 =..?
First, we'll begin by converting 25mL to L. This can be achieved by doing the following:
1000mL = 1L
Therefore, 25mL = 25/1000 = 0.025L
Now, we can obtain the number of mole of HNO3 present in the solution as follow:
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 0.1 x 0.025
Mole = 2.5x10^–3 mole.
Therefore, 2.5x10^–3 mole of HNO3 is present in the solution.