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garri49 [273]
3 years ago
15

PLEASE HELP 15 POINTS!!!!!!

Mathematics
1 answer:
pychu [463]3 years ago
7 0
Area of a triangle: (b*h) /2
So :
(14,5 * 10.5) /2
=152,25 /2
= 76.125
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Simplify.
Dafna11 [192]

Answer:

C. 2x^2-7x+7

Step-by-step explanation:

(3x^2-2x+2)-(x^2+5x-5)     <em>Given</em>

From the given you will subtract like terms from both parenthesis.

3x^2-x^2=2x^2

-2x-5x=-7x

2-(-5)=7                      

6 0
3 years ago
What is the distance between the ends of the class
aleksandrvk [35]
Using tan50=p/14=p=14*tan50
total distance betn the end of the class = 28*tan50=53.6910052ft
5 0
3 years ago
The radius of a cylinder is 3 cm and the height is 6 cm.
Ratling [72]

Answer

Step-by-step explanation:

A=2πrh+2πr2=2·π·3·6+2·π·32≈169.646

5 0
3 years ago
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7. lid fills his sports bottle with 1.2 liters of water After his bike ride he drinks milliliters of the water How much waters le
Goryan [66]
1 litre = 1000 millilitres so 1200-200= 1000 millilitres left or 1 litre left
3 0
4 years ago
Find the arc length and area of a sector with radius R =60 inches and central angle equals 30° round your answer to the nearest
Black_prince [1.1K]

Answer:

(a)31.42 inches

(b)942.48 Square Inches

Step-by-step explanation:

Given a sector of a circle with the following dimensions:

Radius of the circle =60 inches

Central Angle of the sector =30°

(a)Arc Length

Arc Length =\dfrac{\theta}{360^\circ}X2\pi r

=\dfrac{30}{360^\circ}X2*60*\pi\\\\=10\pi\\\\=31.42$ Inches (correct to the nearest hundredth)

(b)Area of the sector

Area of the sector =\dfrac{\theta}{360^\circ}X\pi r^2

=\dfrac{30}{360^\circ}X\pi*60^2\\\\=300\pi\\\\=942.48$ Square Inches (correct to the nearest hundredth)

3 0
3 years ago
Read 2 more answers
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