Step-by-step explanation:
We want to find two things-- the speed of the boat in still water and the speed of the current. Each of these things will be represented by a different variable:
B = speed of the boat in still water
C = speed of the current
Since we have two variables, we will need to find a system of two equations to solve.
How do we find the two equations we need?
Rate problems are based on the relationship Distance = (Rate)(Time).
Fill in the chart with your data (chart attached)
The resulting speed of the boat (traveling upstream) is B-C miles per hour. On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour. The resulting speed of the boat (traveling downstream) is B+C miles per hour. Put this info in the second column in the chart. Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!
I don't know this. Sorry. Good luck
Answer:
i just took the test, so its b. 84
i dont know hwy
Disclaimer- this is all assuming that "semi monthly" means twice a month. if it doesn't, ignore this answer
A- if semi monthly is half a month, then 4 times 2 is 8, and 8 times 12 is 96,000.
B- If there are 4 weeks in a month and 4000$ accounts for half of that pay, then the weekly pay is 2000, making the bi-weekly pay 1000.
C- The monthly pay is 8,000$ because 4,000 x 2 is 8,000
D- The weekly pay is 2,000$ because the monthly pay is 8,000$ and there are 4 weeks in a month
E- I do not know the hours at this job and therefore cannot answer this
A = D/BC. In order to isolate A, all you do is divide by BC