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Anit [1.1K]
4 years ago
9

The sum of three consecutive integers is 267. What is the largest integer? (1 point)

Mathematics
2 answers:
sukhopar [10]4 years ago
3 0

Answer:

88+89+90=267 x=90

Step-by-step explanation:

the answer is 90 because maf may i have brainly plz

labwork [276]4 years ago
3 0

Answer:

88,89,90 (the largest number

Step-by-step explanation:

x+x +1 +x +2 =267

3x +3 =267

3x=267 - 3

3x=264

x=264 :3

x=88 (the first number

88 +1 =89 (the second number

88 +2 =90 (the third number, the largest

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Find the solution of the Quadratic Equation 2X^2 + 2x - 12 = 0 note: X^2 means x to the power of 2
allsm [11]

x=3 and x= -2

Step-by-step explanation:

we could simplify it to x*2 + x -6 = 0

then 2 numbers whose sum is 1 and product is -6

the numbers are 3 and -2

3 0
3 years ago
A sample of 12 measurements has a mean of 16.5, and a sample of 15 measurements has a mean of 18.6. Find the mean of all 27 meas
Wewaii [24]

Answer: 17.67

Step-by-step explanation:

Given

Sample  of 12 measurements has a mean of 16.5 and

a sample of 15 measurements has a mean of 18.6

Take \bar{x_1},n_1 be the mean and no of measurements

and \bar{x_2},n_2 be the mean and no of measurements in second case

\therefore \bar{x_1}=\dfrac{\sum a_1}{n_1}\\\\\Rightarrow \sum a_1=\bar{x_1}\times n_1\\\\\Rightarrow \sum a_1=198\quad \ldots(1)

Similarly,

\therefore \bar{x_2}=\dfrac{\sum a_2}{n_2}\\\\\Rightarrow \sum a_2=\bar{x_2}\times n_2\\\\\Rightarrow \sum a_2=279\quad \ldots(2)

Mean of 27 measurements

\Rightarrow \bar{x_3}=\dfrac{\sum a_1+\sum a_2}{n_1+n_2}\\\\\Rightarrow \bar{x_3}=\dfrac{198+279}{12+15}\\\\\Rightarrow \bar{x_3}=\dfrac{477}{27}\\\\\Rightarrow \bar{x_3}=17.67

4 0
3 years ago
Add parentheses to make 5×9-4×6
Ivanshal [37]

(5x9)-(4x6) if you add parenthese

8 0
3 years ago
Which of the following expression is equal to x^2+25?
nignag [31]
A: (x + 5i)^2
= (x + 5i)(x + 5i)
= (x)(x) + (x)(5i) + (5i)(x) + (5i)(5i)
= x^2 + 5ix + 5ix + 25i^2
= 25i^2 + 10ix + x^2


B: (x - 5i)^2
= (x  +   - 5i)(x +  - 5i)
= (x)(x) + (x)(- 5i) + (- 5i)(x) + (- 5i)(- 5i)
= x^2 - 5ix - 5ix + 25i^2
= 25i^2 - 10ix + x^2


C: (x - 5i)(x + 5i)
= (x +  - 5i)(x + 5i)
= (x)(x) + (x)(5i) + (- 5i)(x) + (- 5i)(5i)
= x^2 + 5ix - 5ix - 25i^2
= 25i^2 + x^2


D: (x + 10i)(x  - 15i)
= (x + 10i)(x +  - 15i)
= (x)(x) + (x)(- 15i) + (10i)(x) + (10i)(- 15i)
= x^2 - 15ix + 10ix - 150i^2
=  - 150i^2 + 5ix + x^2



Hope that helps!!!

6 0
3 years ago
Read 2 more answers
Common Tangents and AAA theorems
lubasha [3.4K]
You know from similar triangles that ...
  KM/KO = LM/LN
  (20 +x)/12 = x/8
Multiplying by 24, we get
  2(20 +x) = 3x
  40 +2x = 3x
Subtracting 2x, we get
  40 = x . . . . . . . . . . the measure of LM

The Pythagorean theorem tells us
  (LN)² +(NM)² = (LM)²
Substituting known values, this becomes
  8² +(NM)² = 40²
  (NM)² = 40² -8² = 1600 -64 = 1536
Then the measure of NM is ...
  NM = √1536 ≈ 39.19

5 0
3 years ago
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