so the value of 1 quarter=0.25 and 1 dime=0.10 so therefor the total value would be 0.25q+0.1d=2.9
total number of coins=20 q+d=20
solve we have 0.25q+0.1d=2.9 and q+d=20 multiply the first equation by 10 2.5q+1d=29
so we have q+d=20 2.5q+d=29
multiply first by -1 and add -q-d=-20 <u>2.5q+d=29 + </u>1.5q+0d=9 1.5q=9 multipliy both sides by 2 3q=18 divide by 3 q=6 subsitute q+d=20 6+d=20 ubtract 6 d=14