Answer:
do you need help with the L and P???????
Step-by-step explanation:
We have trapezoid with congruent legs.
30x + 11y = 2x + 3
28x +11y = 3
Also we have
30x + 11y = 12
We got 2 equations:
30x + 11y = 12
28x +11y = 3 (*-1) -----> -28x -11y = -3
30x + 11y = 12
<u> -28x -11y = -3</u>
2x = 9
x=9/2
30x + 11y = 12 ------> 30*9/2 +11y =12 ------> 135+11y =12, ---> 11y = - 123,
y= - 123/11
The LCM of 24 and 30 is 120.
The total number of articles is 14 and only 7 can be published. Since what is asked is the ways to assemble the 7 articles, this is a permutation problem.
14P7 = <span>17297280 ways
If order is not of concern, the problem is just a combination problem
14C7 = </span><span>3432 ways</span><span />
It would be B. because it's just 7 times 1.5
