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3 years ago

14

Which projectiles will be visibly affected by air resistance when they fall?

1 answer:

NemiM [27]3 years ago

4 0

Any object that is launched as a projectile will lose speed and, as a result, altitude, as it travels through the air. The rate at which the object loses speed and altitude depends on the amount of force that way applied to it when it was launched. It is also dependent on the size and shape of the item. This is why something like, say, a football is much faster to fall to the ground than a bullet.

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How many molecules are there in 39 grams of water

Llana [10]

Answer:

39 g H2O contains 1.3 ×1024molecules H2O.

Explanation:

8 0

3 years ago

Sometimes a person cannot clearly see objects close up or far away. To correct this type of vision, bifocals are often used. The

Alexxx [7]

Answer:

The power of top half of the lens is 0.55 Diopters.

Explanation:

Since, the person can see an object at a distance between 34 cm and 180 cm away from his eyes. Therefore, 180 cm must be the focal length of the upper part of lens, as the top half of the lens is used to see the distant objects.

The general formula for power of a lens is:

Power = 1/Focal Length in meters

Therefore, for the top half of the lens:

Power = 1/1.8 m

<u>Power = 0.55 Diopters</u>

3 0

3 years ago

At the end of cylindrical rod of length l = 1 m and mass M = 1 kg rotating horizontaly along the vertical axis in its center wit

matrenka [14]

Answer:

w = 0.943 rad / s

Explanation:

For this problem we can use the law of conservation of angular momentum

Starting point. With the mouse in the center

L₀ = I w₀

Where The moment of inertia (I) of a rod that rotates at one end is

I = 1/3 M L²

Final point. When the mouse is at the end of the rod

$L_{f}$ = I w + m L² w

As the system is formed by the rod and the mouse, the forces during the movement are internal, therefore the angular momentum is conserved

L₀ = L_{f}

I w₀ = (I + m L²) w

w = I / I + m L²) w₀

We substitute the moment of inertia

w = 1/3 M L² / (1/3 M + m) L² w₀

w = 1 / 3M / (M / 3 + m) w₀

We substitute the values

w = 1/3 / (1/3 + 0.02) w₀

w = 0.943 w₀

To finish the calculation the initial angular velocity value is needed, if we assume that this value is w₀ = 1 rad / s

w = 0.943 rad / s

3 0

3 years ago

A material that can easily flow is called aa. fluid.

Fiesta28 [93]

I'm pretty sure it would be A. As fluids are able to move and flow pretty easily.

7 0

3 years ago

An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 17601760 × 103 seconds (ab

Yuliya22 [10]

Answer:

The value is $a_r = 3.81 *10^{-3} m/s^2$

Explanation:

Generally the moon's radial acceleration is mathematically represented as

$a_r = r * w^2$

Here $w$ is the angular velocity which is mathematically represented as

$w =\frac{2 \pi }{ T}$

substituting $1760 * 10^3 \ seconds$ for T(i.e the period of the moon ) we have

$w =\frac{2 * 3.142 }{ 1760 * 10^3}$

=> $w = 3.57 *10^{-6} \ rad/s$

From the question r(which is the radius of the orbit ) is evaluated as

$r = R + H$

substitute $3.60 * 10^6 m$ for R and $295.0 * 10^6 \ m$ H

$r = 295.0 * 10^6 +3.60 * 10^6$

=> $r = 2.986 *10^{8} \ m$

So

$a_r = 2.986 *10^{8} * ( 3.57 *10^{-6} )^2$

$a_r = 3.81 *10^{-3} m/s^2$

4 0

3 years ago