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3 years ago

Pressure can affect the density of Solids Liquids Gases Metals

Physics

1 answer:

gtnhenbr [62]3 years ago

7 0

Answer;

-Gases

Explanation;

-Pressure can affect the density of gases.

-Density of gases changes with pressure and temperature because gases are compressible fluid and because they are compressible, when pressure increases molecules come closer to each other which means increase in density and when pressure drops molecules of gases become free to expand and get away from each other which density decrease.

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Why is MA always less than VR?

jarptica [38.1K]

Answer:

$\boxed{ \bold{ \boxed{ \sf{see \: below}}}}$

Explanation:

MA ( Mechanical Advantage ) is always less than VR ( Velocity Ratio ) because MA is reduced by friction but VR is not affected by friction.

Hope I helped!

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3 years ago

Who is responsible for documenting the crime scene in detail and collecting physical

miv72 [106K]

Crime scenes contain physical evidence that is pertinent to a criminal investigation. This evidence is collected by crime scene investigators (CSIs) and law enforcement. The location of a crime scene can be the place where the crime took place or can be any area that contains evidence from the crime itself.

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3 years ago

How large an expansion gap should be left between steel railroad rails if they may reach a maximum temperature 40.0°C greater th

ella [17]

Answer:

19.68 × 10⁻³ m

Explanation:

Given;

Original Length, L₁ = 41.0 m

Temperature Change, ΔT = 40.0°C

Thermal Linear expansion of steel is given to be, ∝ $_{steel}$ = 12 × 10⁻⁶ /°C

Generally, Linear expansivity is expressed as;

∝ = ΔL / L₁ΔT

Where

∝ is the Linear expansivity

ΔL is the change in length, L₂ - L₁

L₂ is the final length

L₁ is the original length

ΔT is the change in temperature θ₂ - θ₁ (Final Temperature - Initial Temperature)

From equation of linear expansivity

ΔL = ∝ $_{steel}$ L₁ΔT

ΔL = 12 × 10⁻⁶ /°C × 41.0 m × 40.0 °C

ΔL = 19.68 × 10⁻³ m

ΔL = 19.68 mm

8 0

3 years ago

At a race car driving event, a staff member notices that the skid marks left by the race car are

krok68 [10]

A car that experiences a deceleration of -41.62 m/s² and comes to a stop after 10.99 m has an initial velocity of 30.60 m/s.

A car experiences a deceleration (a) of -41.62 m/s² and comes to a stop (final velocity = v = 0 m/s) after 10.99 m (s).

We can calculate the initial velocity of the car (u) using the following kinematic equation.

$v^{2} = u^{2} + 2as\\\\u = \sqrt[]{v^{2}-2as} = \sqrt[]{(0m/s)^{2}-2(-42.61m/s^{2} )(10.99m)} = 30.60m/s$

A car that experiences a deceleration of -41.62 m/s² and comes to a stop after 10.99 m has an initial velocity of 30.60 m/s.

Learn more: brainly.com/question/14851168

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2 years ago

FIND THE WEIGHT OF A 80 KG MAN ON THE SURFACE OF MOON? WHAT SHOULD BE HISS MASS ON THE EARTH AND ON THE MOON? (ge = 9.8 m/s2 ; g

elena55 [62]

Weight = (mass) x (acceleration of gravity at the place where the mass is) .

Man's mass = 80 kg

His weight on Earth = (80 kg) x (9.8 m/s²) = 784 newtons (about 176 pounds)

His weight on the Moon = (80 kg) x (1.63 m/s²) = 130.4 newtons (about 29.2 pounds)

His mass is 80 kg. Mass is the thing about him that doesn't change.
He has the same mass on the Earth, on the Moon, or anywhere.

8 0

2 years ago