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Vika [28.1K]
3 years ago
15

Find the frequency of a wave of wavelength 2.5m and speed 400 m/s

Physics
1 answer:
Sedaia [141]3 years ago
7 0

Answer:

The frequency of wave is 160Hz.

Explanation:

Given that the formula of speed is V = f×λ where V represents speed, f is frequency and λ is wavelength.

So first thing, you have to make frequency the subject by dividing wavelength on both sides :

v = f \times λ \:

v \div  λ =  f \times λ \div λ

f =  \frac{v}{λ}

Next you have to substitute the value of v and f into the formula :

Let λ = 2.5m,

Let v = 400m/s,

f =  \frac{400}{2.5}

f = 160Hz

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An object 82 cm high forms a virtual image 4.1 cm high located 4.6 cm behind a mirror. Find the object distance.
ioda

Answer:

The object distance is 92 cm.  

Explanation:

let v be the image distance and h be the height of the image, let u the be the object distance and H be the height of the object.

then, the magification of the mirror is given by:

m = -v/u and m = h/H

so, -v/u = h/H

         u = -v×H/h

            = -(-4.6)×(82)/(4.1)

            = 92 cm

Therefore, the object distance is 92 cm.

8 0
3 years ago
An equation for the period of a planet is 4 pie² r³/Gm where T is in secs, r is in meters, G is in m³/kgs² m is in kg, show that
marishachu [46]

Answer:

\displaystyle T = \sqrt{\frac{4\, \pi^{2} \, r^{3}}{G \cdot m}}.

The unit of both sides of this equation are \rm s.

Explanation:

The unit of the left-hand side is \rm s, same as the unit of T.

The following makes use of the fact that for any non-zero value x, the power x^{-1} is equivalent to \displaystyle \frac{1}{x}.

On the right-hand side of this equation:

  • \pi has no unit.
  • The unit of r is \rm m.
  • The unit of G is \displaystyle \rm \frac{m^{3}}{kg \cdot s^{2}}, which is equivalent to \rm m^{3} \cdot kg^{-1} \cdot s^{-2}.
  • The unit of m is \rm kg.

\begin{aligned}& \rm \sqrt{\frac{(m)^{3}}{(m^{3} \cdot kg^{-1} \cdot s^{-2}) \cdot (kg)}} \\ &= \rm \sqrt{\frac{m^{3}}{m^{3} \cdot s^{-2}}} = \sqrt{s^{2}} = s\end{aligned}.

Hence, the unit on the right-hand side of this equation is also \rm s.

8 0
3 years ago
the average velocity of a duck is zero as it goes from t=0 to t=120 s. describe the displacement of the duck for that interval
podryga [215]

Answer:

The displacement, s= 0 m

Explanation:

Given data,

The average velocity of the duck, v = 0 m/s

The time interval of the velocity, t₁ = 0 and t₂ = 120 s,

                                       ∴                 Δt =  t₂ - t₁

                                                                = 120 s

The displacement of the duck is given by the formula,

                                         s = v x Δt

                                            = 0 m/s x 120 s

                                            = 0 m

Hence, the displacement of the duck is, s = 0 m

8 0
4 years ago
Pleasee l need help ​
blsea [12.9K]

(a) 5 m/s

Explanation:

At its maximum height, only its horizontal component of its velocity is nonzero. We know that

v_{x} = v_{0}\cos60 = (10 \:  \frac{m}{s})(0.5) = 5 \:  \frac{m}{s}

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3 years ago
Analyze data table #1 and then create a line graph comparing speed and time.
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I don’t know what the answer is to the question but if I don’t answer the question I will be mad at the
8 0
3 years ago
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